YES

(VAR x x0)
(RULES
  p(x) -> x
  s(x0) -> x0
  +(x,0()) -> x
)

(COMMENT
Termination is shown by EKBO with interpretations on natural numbers

  p_A(x1) = 1
  0_A = 1
  s_A(x1) = x1 + 1
  +_A(x1,x2) = x1 + 2
  0#_A = 0
  +#_A(x1,x2) = x1 + x2

weights

  w0 = 1
  w(p) = 1
  w(0) = 1
  w(s) = 1
  w(+) = 0

and precedence:

+ > p > s > 0
)