YES

(VAR x x0)
(RULES
  c(x) -> x
  b(x0) -> x0
  a(x) -> x
)

(COMMENT
Termination is shown by EKBO with interpretations on natural numbers

  a_A(x1) = 6
  c_A(x1) = x1 + 1
  b_A(x1) = 3
  c#_A(x1) = x1

weights

  w0 = 1
  w(a) = 27
  w(c) = 5
  w(b) = 1

and precedence:

a > c > b
)