YES

TRS:

  f(c(a(),z,x)) -> b(a(),z)
  b(x,b(z,y)) -> f(b(f(f(z)),c(x,z,y)))
  b(y,z) -> z

max/plus interpretations on N:

  f_A(x1) = max{1, -4 + x1}
  f#_A(x1) = max{1, 3}
  c_A(x1,x2,x3) = max{8, 13 + x1, 8 + x2, -1}
  c#_A(x1,x2,x3) = max{4, 2 + x1, -14 + x2, -15}
  a_A = 9
  a#_A = 5
  b_A(x1,x2) = max{18, 9 + x1, x2}
  b#_A(x1,x2) = max{0, 2 + x1, -14 + x2}

precedence:

  c = b > a > f