YES

Problem:
 +(0(),y) -> y
 +(s(x),y) -> s(+(x,y))
 +(x,0()) -> x
 +(x,s(y)) -> s(+(x,y))

Proof:
 Matrix Interpretation Processor:
  dimension: 1
  interpretation:
   [s](x0) = x0 + 4,
   
   [+](x0, x1) = x0 + x1 + 3,
   
   [0] = 0
  orientation:
   +(0(),y) = y + 3 >= y = y
   
   +(s(x),y) = x + y + 7 >= x + y + 7 = s(+(x,y))
   
   +(x,0()) = x + 3 >= x = x
   
   +(x,s(y)) = x + y + 7 >= x + y + 7 = s(+(x,y))
  problem:
   +(s(x),y) -> s(+(x,y))
   +(x,s(y)) -> s(+(x,y))
  Matrix Interpretation Processor:
   dimension: 1
   interpretation:
    [s](x0) = x0 + 1,
    
    [+](x0, x1) = x0 + 4x1 + 7
   orientation:
    +(s(x),y) = x + 4y + 8 >= x + 4y + 8 = s(+(x,y))
    
    +(x,s(y)) = x + 4y + 11 >= x + 4y + 8 = s(+(x,y))
   problem:
    +(s(x),y) -> s(+(x,y))
   Matrix Interpretation Processor:
    dimension: 3
    interpretation:
                    [0]
     [s](x0) = x0 + [1]
                    [1],
     
                   [1 0 1]     [1 0 1]  
     [+](x0, x1) = [0 1 0]x0 + [0 1 0]x1
                   [0 1 0]     [0 0 0]  
    orientation:
                 [1 0 1]    [1 0 1]    [1]    [1 0 1]    [1 0 1]    [0]            
     +(s(x),y) = [0 1 0]x + [0 1 0]y + [1] >= [0 1 0]x + [0 1 0]y + [1] = s(+(x,y))
                 [0 1 0]    [0 0 0]    [1]    [0 1 0]    [0 0 0]    [1]            
    problem:
     
    Qed