YES

Problem:
 F(x,y) -> c(A())
 G(x) -> x
 h(x) -> c(x)

Proof:
 Matrix Interpretation Processor:
  dimension: 3
  interpretation:
             [1 0 0]     [1]
   [h](x0) = [0 0 0]x0 + [0]
             [0 0 0]     [0],
   
             [1 1 1]     [1]
   [G](x0) = [1 1 1]x0 + [1]
             [1 1 1]     [1],
   
             [1 0 0]  
   [c](x0) = [0 0 0]x0
             [0 0 0]  ,
   
         [0]
   [A] = [0]
         [0],
   
                 [1 0 0]     [1 0 0]     [1]
   [F](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [0]
                 [0 0 0]     [0 0 0]     [0]
  orientation:
            [1 0 0]    [1 0 0]    [1]    [0]         
   F(x,y) = [0 0 0]x + [0 0 0]y + [0] >= [0] = c(A())
            [0 0 0]    [0 0 0]    [0]    [0]         
   
          [1 1 1]    [1]         
   G(x) = [1 1 1]x + [1] >= x = x
          [1 1 1]    [1]         
   
          [1 0 0]    [1]    [1 0 0]        
   h(x) = [0 0 0]x + [0] >= [0 0 0]x = c(x)
          [0 0 0]    [0]    [0 0 0]        
  problem:
   
  Qed