NO

Problem:
 f(f(x,y),z) -> f(x,f(y,z))
 f(x,y) -> f(y,x)

Proof:
 Containment Processor: loop length: 1
                        terms:
                         f(x,y)
                        context: []
                        substitution:
                         x -> y
                         y -> x
  Qed