NO

Problem:
 f(x,y,f(z,u,v)) -> f(f(x,y,z),u,f(x,y,v))

Proof:
 Containment Processor:
  loop length: 1
  terms:
   f(x,y,f(z,u,v))
  context: []
  substitution:
   u -> y
   v -> v
   x -> f(x,y,z)
   y -> u
   z -> x
  Qed