NO

Problem:
 f(h(x)) -> f(i(x))
 f(i(x)) -> a()
 i(x) -> h(x)

Proof:
 Matrix Interpretation Processor:
  dimension: 1
  interpretation:
   [a] = 0,
   
   [i](x0) = x0 + 4,
   
   [f](x0) = 5x0 + 4,
   
   [h](x0) = x0 + 4
  orientation:
   f(h(x)) = 5x + 24 >= 5x + 24 = f(i(x))
   
   f(i(x)) = 5x + 24 >= 0 = a()
   
   i(x) = x + 4 >= x + 4 = h(x)
  problem:
   f(h(x)) -> f(i(x))
   i(x) -> h(x)
  Unfolding Processor:
   loop length: 2
   terms:
    f(h(x4))
    f(i(x4))
   context: []
   substitution:
    x4 -> x4
   Qed