YES Confluence Proof

Confluence Proof

by csi

Input

The rewrite relation of the following TRS is considered.

h(c,c) h(b,f(b))
f(h(a,h(c,a))) c
h(c,b) f(a)

Proof

1 Redundant Rules Transformation

To prove that the TRS is (non-)confluent, we show (non-)confluence of the following modified system:

h(c,b) f(a)
f(h(a,h(c,a))) c
h(c,c) h(b,f(b))

All redundant rules that were added or removed can be simulated in 2 steps .

1.1 Critical Pair Closing System

Confluence is proven using the following terminating critical-pair-closing-system R:

There are no rules.

1.1.1 R is empty

There are no rules in the TRS. Hence, it is terminating.

Tool configuration

csi