YES
0 QTRS
↳1 QTRSRRRProof (⇔, 0 ms)
↳2 QTRS
↳3 RisEmptyProof (⇔, 0 ms)
↳4 YES
f(+(x, 0)) → f(x)
+(x, +(y, z)) → +(+(x, y), z)
With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly:
POL(+(x1, x2)) = 2 + x1 + 2·x2
POL(0) = 0
POL(f(x1)) = 2·x1
f(+(x, 0)) → f(x)
+(x, +(y, z)) → +(+(x, y), z)