YES proof of Mixed_TRS_jones6.trs # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 jera 20211004 unpublished Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 68 ms] (2) QTRS (3) QTRSRRRProof [EQUIVALENT, 0 ms] (4) QTRS (5) QTRSRRRProof [EQUIVALENT, 0 ms] (6) QTRS (7) RisEmptyProof [EQUIVALENT, 0 ms] (8) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(a, empty) -> g(a, empty) f(a, cons(x, k)) -> f(cons(x, a), k) g(empty, d) -> d g(cons(x, k), d) -> g(k, cons(x, d)) Q is empty. ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(cons(x_1, x_2)) = 1 + x_1 + x_2 POL(empty) = 0 POL(f(x_1, x_2)) = 1 + 2*x_1 + 2*x_2 POL(g(x_1, x_2)) = 2*x_1 + x_2 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: f(a, empty) -> g(a, empty) g(cons(x, k), d) -> g(k, cons(x, d)) ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(a, cons(x, k)) -> f(cons(x, a), k) g(empty, d) -> d Q is empty. ---------------------------------------- (3) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(cons(x_1, x_2)) = x_1 + x_2 POL(empty) = 0 POL(f(x_1, x_2)) = 2*x_1 + 2*x_2 POL(g(x_1, x_2)) = 2 + x_1 + x_2 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: g(empty, d) -> d ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(a, cons(x, k)) -> f(cons(x, a), k) Q is empty. ---------------------------------------- (5) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(cons(x_1, x_2)) = 1 + x_1 + x_2 POL(f(x_1, x_2)) = x_1 + 2*x_2 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: f(a, cons(x, k)) -> f(cons(x, a), k) ---------------------------------------- (6) Obligation: Q restricted rewrite system: R is empty. Q is empty. ---------------------------------------- (7) RisEmptyProof (EQUIVALENT) The TRS R is empty. Hence, termination is trivially proven. ---------------------------------------- (8) YES