YES proof of SK90_2.21.trs # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 jera 20211004 unpublished Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 71 ms] (2) QTRS (3) RisEmptyProof [EQUIVALENT, 0 ms] (4) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: bin(x, 0) -> s(0) bin(0, s(y)) -> 0 bin(s(x), s(y)) -> +(bin(x, s(y)), bin(x, y)) Q is empty. ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: Quasi precedence: bin_2 > 0 > s_1 bin_2 > +_2 > s_1 Status: bin_2: multiset status 0: multiset status s_1: multiset status +_2: multiset status With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: bin(x, 0) -> s(0) bin(0, s(y)) -> 0 bin(s(x), s(y)) -> +(bin(x, s(y)), bin(x, y)) ---------------------------------------- (2) Obligation: Q restricted rewrite system: R is empty. Q is empty. ---------------------------------------- (3) RisEmptyProof (EQUIVALENT) The TRS R is empty. Hence, termination is trivially proven. ---------------------------------------- (4) YES