YES

TRS:

  f(0()) -> s(0())
  f(s(0())) -> s(0())
  f(s(s(x))) -> f(f(s(x)))

linear polynomial interpretations on N:

  f_A(x1) = 4
  f#_A(x1) = 2
  0_A = 1
  0#_A = 0
  s_A(x1) = 3
  s#_A(x1) = x1

precedence:

  f > s > 0