YES

TRS:

  rev(ls) -> r1(ls,empty())
  r1(empty(),a) -> a
  r1(cons(x,k),a) -> r1(k,cons(x,a))

linear polynomial interpretations on N:

  rev_A(x1) = 1
  rev#_A(x1) = x1 + 3
  r1_A(x1,x2) = x2
  r1#_A(x1,x2) = x2 + 1
  empty_A = 1
  empty#_A = 0
  cons_A(x1,x2) = 0
  cons#_A(x1,x2) = 0

precedence:

  rev > r1 = empty > cons