YES

TRS:

  +(x,0()) -> x
  +(x,s(y)) -> s(+(x,y))
  +(0(),s(y)) -> s(y)
  s(+(0(),y)) -> s(y)

linear polynomial interpretations on N:

  +_A(x1,x2) = x1 + x2 + 1
  +#_A(x1,x2) = x1 + x2
  0_A = 1
  0#_A = 0
  s_A(x1) = x1 + 3
  s#_A(x1) = 2

precedence:

  + > 0 = s