YES

TRS:

  rev(a()) -> a()
  rev(b()) -> b()
  rev(++(x,y)) -> ++(rev(y),rev(x))
  rev(++(x,x)) -> rev(x)

linear polynomial interpretations on N:

  rev_A(x1) = 1
  rev#_A(x1) = 1
  a_A = 1
  a#_A = 0
  b_A = 1
  b#_A = 0
  ++_A(x1,x2) = x2
  ++#_A(x1,x2) = 0

precedence:

  rev > a = b = ++