YES

TRS:

  U11(tt(),N) -> activate(N)
  U21(tt(),M,N) -> s(plus(activate(N),activate(M)))
  and(tt(),X) -> activate(X)
  isNat(n__0()) -> tt()
  isNat(n__plus(V1,V2)) -> and(isNat(activate(V1)),n__isNat(activate(V2)))
  isNat(n__s(V1)) -> isNat(activate(V1))
  plus(N,0()) -> U11(isNat(N),N)
  plus(N,s(M)) -> U21(and(isNat(M),n__isNat(N)),M,N)
  0() -> n__0()
  plus(X1,X2) -> n__plus(X1,X2)
  isNat(X) -> n__isNat(X)
  s(X) -> n__s(X)
  activate(n__0()) -> 0()
  activate(n__plus(X1,X2)) -> plus(X1,X2)
  activate(n__isNat(X)) -> isNat(X)
  activate(n__s(X)) -> s(X)
  activate(X) -> X

linear polynomial interpretations on N:

  U11_A(x1,x2) = x2
  U11#_A(x1,x2) = x2 + 2
  tt_A = 1
  tt#_A = 1
  activate_A(x1) = x1
  activate#_A(x1) = x1 + 1
  U21_A(x1,x2,x3) = x2 + x3 + 11
  U21#_A(x1,x2,x3) = x2 + x3 + 9
  s_A(x1) = x1 + 3
  s#_A(x1) = 3
  plus_A(x1,x2) = x1 + x2 + 8
  plus#_A(x1,x2) = x1 + x2 + 8
  and_A(x1,x2) = x1 + x2
  and#_A(x1,x2) = x2 + 2
  isNat_A(x1) = x1 + 4
  isNat#_A(x1) = x1 + 4
  n__0_A = 1
  n__0#_A = 0
  n__plus_A(x1,x2) = x1 + x2 + 8
  n__plus#_A(x1,x2) = x2 + 7
  n__isNat_A(x1) = x1 + 4
  n__isNat#_A(x1) = 3
  n__s_A(x1) = x1 + 3
  n__s#_A(x1) = 2
  0_A = 1
  0#_A = 1

precedence:

  U21 > plus > U11 = n__plus = n__s > activate > s = 0 > isNat = n__0 > tt = and = n__isNat