YES

TRS:

  f(a(),f(f(a(),x),a())) -> f(f(a(),f(a(),x)),a())

linear polynomial interpretations on N:

  f_A(x1,x2) = x1 + x2 + 1
  f#_A(x1,x2) = x2 + 1
  a_A = 0
  a#_A = 0

precedence:

  f > a