YES

TRS:

  times(x,0()) -> 0()
  times(x,s(y)) -> plus(times(x,y),x)
  plus(x,0()) -> x
  plus(0(),x) -> x
  plus(x,s(y)) -> s(plus(x,y))
  plus(s(x),y) -> s(plus(x,y))

max/plus interpretations on N:

  times_A(x1,x2) = max{3, 4 + x1, 3}
  times#_A(x1,x2) = max{5, 5, 3}
  0_A = 4
  0#_A = 4
  s_A(x1) = max{3, 4}
  s#_A(x1) = max{1, -1}
  plus_A(x1,x2) = max{4, x1, 1 + x2}
  plus#_A(x1,x2) = max{0, 2, 2}

precedence:

  times > 0 = plus > s