YES

TRS:

  f(s(x),y,y) -> f(y,x,s(x))

max/plus interpretations on N:

  f_A(x1,x2,x3) = max{0, 1 + x1, 0, 1 + x3}
  f#_A(x1,x2,x3) = max{3, x1, 1 + x2, -5 + x3}
  s_A(x1) = max{0, 4 + x1}
  s#_A(x1) = max{2, -6}

precedence:

  f > s