YES

TRS:

  minus(minus(x)) -> x
  minus(h(x)) -> h(minus(x))
  minus(f(x,y)) -> f(minus(y),minus(x))

max/plus interpretations on N:

  minus_A(x1) = max{1, 1 + x1}
  minus#_A(x1) = max{1, 3 + x1}
  h_A(x1) = max{1, 3 + x1}
  h#_A(x1) = max{5, 0}
  f_A(x1,x2) = max{1, 2 + x1, 2 + x2}
  f#_A(x1,x2) = max{0, 2, 4 + x2}

precedence:

  minus > h = f