YES

TRS:

  f(+(x,0())) -> f(x)
  +(x,+(y,z)) -> +(+(x,y),z)

max/plus interpretations on N:

  f_A(x1) = max{0, x1}
  f#_A(x1) = max{0, 1}
  +_A(x1,x2) = max{7, x1, 3 + x2}
  +#_A(x1,x2) = max{2, 3, 1 + x2}
  0_A = 1
  0#_A = 0

precedence:

  + > f = 0