YES

TRS:

  a(b(x)) -> b(b(a(x)))

max/plus interpretations on N:

  a_A(x1) = max{2, 1}
  a#_A(x1) = max{1, -1}
  b_A(x1) = max{2, 2}
  b#_A(x1) = max{0, 1}

precedence:

  a > b