YES

TRS:

  +(0(),y) -> y
  +(s(x),0()) -> s(x)
  +(s(x),s(y)) -> s(+(s(x),+(y,0())))

max/plus interpretations on N:

  +_A(x1,x2) = max{1, 2, x2}
  +#_A(x1,x2) = max{1, 2, 4 + x2}
  0_A = 1
  0#_A = 0
  s_A(x1) = max{2, -1}
  s#_A(x1) = max{6, -1}

precedence:

  + > s > 0