YES

TRS:

  a(b(x)) -> a(c(b(x)))

max/plus interpretations on N:

  a_A(x1) = max{0, 6 + x1}
  a#_A(x1) = max{1, 8 + x1}
  b_A(x1) = max{2, -2 + x1}
  b#_A(x1) = max{2, 10}
  c_A(x1) = max{1, -3 + x1}
  c#_A(x1) = max{0, -2 + x1}

precedence:

  a > b > c