YES

TRS:

  2nd(cons(X,n__cons(Y,Z))) -> activate(Y)
  from(X) -> cons(X,n__from(n__s(X)))
  cons(X1,X2) -> n__cons(X1,X2)
  from(X) -> n__from(X)
  s(X) -> n__s(X)
  activate(n__cons(X1,X2)) -> cons(activate(X1),X2)
  activate(n__from(X)) -> from(activate(X))
  activate(n__s(X)) -> s(activate(X))
  activate(X) -> X

max/plus interpretations on N:

  2nd_A(x1) = max{5, x1}
  2nd#_A(x1) = max{0, 8}
  cons_A(x1,x2) = max{4, x1, 2 + x2}
  cons#_A(x1,x2) = max{4, 1, 6}
  n__cons_A(x1,x2) = max{0, x1, 1 + x2}
  n__cons#_A(x1,x2) = max{0, 2, 0}
  activate_A(x1) = max{5, 2 + x1}
  activate#_A(x1) = max{5, 8}
  from_A(x1) = max{7, 2 + x1}
  from#_A(x1) = max{7, 2}
  n__from_A(x1) = max{5, 2 + x1}
  n__from#_A(x1) = max{1, 3}
  n__s_A(x1) = max{0, -1}
  n__s#_A(x1) = max{3, 1}
  s_A(x1) = max{3, -2}
  s#_A(x1) = max{4, 4}

precedence:

  2nd = n__cons = s > activate > from > cons = n__from = n__s