YES

TRS:

  terms(N) -> cons(recip(sqr(N)),n__terms(s(N)))
  sqr(0()) -> 0()
  sqr(s(X)) -> s(add(sqr(X),dbl(X)))
  dbl(0()) -> 0()
  dbl(s(X)) -> s(s(dbl(X)))
  add(0(),X) -> X
  add(s(X),Y) -> s(add(X,Y))
  first(0(),X) -> nil()
  first(s(X),cons(Y,Z)) -> cons(Y,n__first(X,activate(Z)))
  terms(X) -> n__terms(X)
  first(X1,X2) -> n__first(X1,X2)
  activate(n__terms(X)) -> terms(X)
  activate(n__first(X1,X2)) -> first(X1,X2)
  activate(X) -> X

max/plus interpretations on N:

  terms_A(x1) = max{11, -10}
  terms#_A(x1) = max{4, 12}
  cons_A(x1,x2) = max{3, -9, x2}
  cons#_A(x1,x2) = max{12, 3, 1}
  recip_A(x1) = max{1, 1}
  recip#_A(x1) = max{12, 2 + x1}
  sqr_A(x1) = max{10, 1}
  sqr#_A(x1) = max{5, 11}
  n__terms_A(x1) = max{11, -11}
  n__terms#_A(x1) = max{12, 11}
  s_A(x1) = max{3, 2}
  s#_A(x1) = max{3, 3}
  0_A = 10
  0#_A = 10
  add_A(x1,x2) = max{3, 2, 2 + x2}
  add#_A(x1,x2) = max{2, 3, 3}
  dbl_A(x1) = max{10, 2}
  dbl#_A(x1) = max{9, 6}
  first_A(x1,x2) = max{2, -1, 11 + x2}
  first#_A(x1,x2) = max{0, 12, 7 + x2}
  nil_A = 2
  nil#_A = 6
  n__first_A(x1,x2) = max{11, -1, 11 + x2}
  n__first#_A(x1,x2) = max{11, -1, 7 + x2}
  activate_A(x1) = max{1, x1}
  activate#_A(x1) = max{12, 2 + x1}

precedence:

  sqr > add = dbl > s = 0 > terms = nil > recip = n__terms = first > cons = n__first > activate