YES

TRS:

  first(0(),X) -> nil()
  first(s(X),cons(Y,Z)) -> cons(Y,n__first(X,activate(Z)))
  from(X) -> cons(X,n__from(n__s(X)))
  first(X1,X2) -> n__first(X1,X2)
  from(X) -> n__from(X)
  s(X) -> n__s(X)
  activate(n__first(X1,X2)) -> first(activate(X1),activate(X2))
  activate(n__from(X)) -> from(activate(X))
  activate(n__s(X)) -> s(activate(X))
  activate(X) -> X

max/plus interpretations on N:

  first_A(x1,x2) = max{12, 6 + x1, 1 + x2}
  first#_A(x1,x2) = max{7, 8 + x1, 14 + x2}
  0_A = 8
  0#_A = 16
  nil_A = 13
  nil#_A = 15
  s_A(x1) = max{0, x1}
  s#_A(x1) = max{13, 13}
  cons_A(x1,x2) = max{0, -8 + x1, x2}
  cons#_A(x1,x2) = max{0, 6 + x1, 2 + x2}
  n__first_A(x1,x2) = max{12, 6 + x1, 1 + x2}
  n__first#_A(x1,x2) = max{11, 11, 14}
  activate_A(x1) = max{2, x1}
  activate#_A(x1) = max{12, 14 + x1}
  from_A(x1) = max{2, x1}
  from#_A(x1) = max{1, 6 + x1}
  n__from_A(x1) = max{1, x1}
  n__from#_A(x1) = max{5, 1}
  n__s_A(x1) = max{0, x1}
  n__s#_A(x1) = max{0, 6}

precedence:

  first = s = from > 0 = cons = n__from = n__s > nil = activate > n__first