YES

TRS:

  first(0(),X) -> nil()
  first(s(X),cons(Y)) -> cons(Y)
  from(X) -> cons(X)

max/plus interpretations on N:

  first_A(x1,x2) = max{2, -1 + x1, 1}
  first#_A(x1,x2) = max{0, -1 + x1, 0}
  0_A = 1
  0#_A = 2
  nil_A = 2
  nil#_A = 1
  s_A(x1) = max{1, -1}
  s#_A(x1) = max{0, 0}
  cons_A(x1) = max{2, 1}
  cons#_A(x1) = max{1, 2}
  from_A(x1) = max{0, 2}
  from#_A(x1) = max{3, 3}

precedence:

  first = s = from > nil = cons > 0