YES

TRS:

  and(tt(),X) -> activate(X)
  plus(N,0()) -> N
  plus(N,s(M)) -> s(plus(N,M))
  activate(X) -> X

max/plus interpretations on N:

  and_A(x1,x2) = max{1, 0, x2}
  and#_A(x1,x2) = max{3, 2, 0}
  tt_A = 0
  tt#_A = 0
  activate_A(x1) = max{1, x1}
  activate#_A(x1) = max{3, 1}
  plus_A(x1,x2) = max{3, 1 + x1, -1}
  plus#_A(x1,x2) = max{1, 1, 1}
  0_A = 0
  0#_A = 0
  s_A(x1) = max{2, -1 + x1}
  s#_A(x1) = max{0, 1}

precedence:

  and = plus > tt = activate = 0 = s