YES

TRS:

  f(x,f(f(a(),a()),a())) -> f(f(a(),f(a(),a())),x)

max/plus interpretations on N:

  f_A(x1,x2) = max{4, 13 + x1, 6 + x2}
  f#_A(x1,x2) = max{0, 3 + x1, 1 + x2}
  a_A = 1
  a#_A = 1

precedence:

  f > a