YES

TRS:

  f(f(a(),f(x,a())),a()) -> f(a(),f(f(x,a()),a()))

max/plus interpretations on N:

  f_A(x1,x2) = max{2, 1, 2}
  f#_A(x1,x2) = max{0, 0, -2 + x2}
  a_A = 2
  a#_A = 1

precedence:

  f > a