YES

TRS:

  f(f(a(),f(a(),a())),x) -> f(x,f(f(a(),a()),a()))

max/plus interpretations on N:

  f_A(x1,x2) = max{6, 6 + x1, 13 + x2}
  f#_A(x1,x2) = max{0, -1 + x1, 1 + x2}
  a_A = 3
  a#_A = 3

precedence:

  f > a