YES TRS: a(a(x)) -> b(b(x)) b(b(a(x))) -> a(b(b(x))) linear polynomial interpretations on N: a_A(x1) = x1 + 3 a#_A(x1) = x1 + 3 b_A(x1) = x1 + 2 b#_A(x1) = x1 + 2 precedence: b > a