YES

TRS:

  *(i(x),x) -> 1()
  *(1(),y) -> y
  *(x,0()) -> 0()
  *(*(x,y),z) -> *(x,*(y,z))

max/plus interpretations on N:

  *_A(x1,x2) = max{0, x1, x2}
  *#_A(x1,x2) = max{0, x1, x2}
  i_A(x1) = max{0, x1}
  i#_A(x1) = max{0, x1}
  1_A = 0
  1#_A = 0
  0_A = 0
  0#_A = 0

precedence:

  i > 1 = 0 > *