YES

TRS:

  f(f(a())) -> c()

max/plus interpretations on N:

  f_A(x1) = max{0, x1}
  f#_A(x1) = max{0, x1}
  a_A = 0
  a#_A = 0
  c_A = 0
  c#_A = 0

precedence:

  f = a > c