YES Problem: norm(nil()) -> 0() norm(g(x,y)) -> s(norm(x)) f(x,nil()) -> g(nil(),x) f(x,g(y,z)) -> g(f(x,y),z) rem(nil(),y) -> nil() rem(g(x,y),0()) -> g(x,y) rem(g(x,y),s(z)) -> rem(x,z) Proof: Matrix Interpretation Processor: dim=1 interpretation: [rem](x0, x1) = 4x0 + x1, [f](x0, x1) = 4x0 + 2x1, [s](x0) = x0, [g](x0, x1) = x0 + 4x1, [0] = 0, [norm](x0) = 4x0 + 6, [nil] = 0 orientation: norm(nil()) = 6 >= 0 = 0() norm(g(x,y)) = 4x + 16y + 6 >= 4x + 6 = s(norm(x)) f(x,nil()) = 4x >= 4x = g(nil(),x) f(x,g(y,z)) = 4x + 2y + 8z >= 4x + 2y + 4z = g(f(x,y),z) rem(nil(),y) = y >= 0 = nil() rem(g(x,y),0()) = 4x + 16y >= x + 4y = g(x,y) rem(g(x,y),s(z)) = 4x + 16y + z >= 4x + z = rem(x,z) problem: norm(g(x,y)) -> s(norm(x)) f(x,nil()) -> g(nil(),x) f(x,g(y,z)) -> g(f(x,y),z) rem(nil(),y) -> nil() rem(g(x,y),0()) -> g(x,y) rem(g(x,y),s(z)) -> rem(x,z) Matrix Interpretation Processor: dim=3 interpretation: [1 0 1] [1 0 0] [rem](x0, x1) = [0 1 0]x0 + [0 0 0]x1 [0 0 1] [0 0 1] , [1 0 1] [1 1 0] [f](x0, x1) = [1 0 0]x0 + [1 1 1]x1 [0 1 0] [0 0 1] , [1 0 0] [0] [s](x0) = [0 0 0]x0 + [0] [0 0 1] [1], [1 0 0] [0] [g](x0, x1) = x0 + [0 0 0]x1 + [1] [0 1 0] [0], [0] [0] = [0] [0], [1 1 0] [norm](x0) = [0 0 0]x0 [0 1 0] , [0] [nil] = [0] [1] orientation: [1 1 0] [1 0 0] [1] [1 1 0] [0] norm(g(x,y)) = [0 0 0]x + [0 0 0]y + [0] >= [0 0 0]x + [0] = s(norm(x)) [0 1 0] [0 0 0] [1] [0 1 0] [1] [1 0 1] [0] [1 0 0] [0] f(x,nil()) = [1 0 0]x + [1] >= [0 0 0]x + [1] = g(nil(),x) [0 1 0] [1] [0 1 0] [1] [1 0 1] [1 1 0] [1 0 0] [1] [1 0 1] [1 1 0] [1 0 0] [0] f(x,g(y,z)) = [1 0 0]x + [1 1 1]y + [1 1 0]z + [1] >= [1 0 0]x + [1 1 1]y + [0 0 0]z + [1] = g(f(x,y),z) [0 1 0] [0 0 1] [0 1 0] [0] [0 1 0] [0 0 1] [0 1 0] [0] [1 0 0] [1] [0] rem(nil(),y) = [0 0 0]y + [0] >= [0] = nil() [0 0 1] [1] [1] [1 0 1] [1 1 0] [0] [1 0 0] [0] rem(g(x,y),0()) = [0 1 0]x + [0 0 0]y + [1] >= x + [0 0 0]y + [1] = g(x,y) [0 0 1] [0 1 0] [0] [0 1 0] [0] [1 0 1] [1 1 0] [1 0 0] [0] [1 0 1] [1 0 0] rem(g(x,y),s(z)) = [0 1 0]x + [0 0 0]y + [0 0 0]z + [1] >= [0 1 0]x + [0 0 0]z = rem(x,z) [0 0 1] [0 1 0] [0 0 1] [1] [0 0 1] [0 0 1] problem: f(x,nil()) -> g(nil(),x) rem(g(x,y),0()) -> g(x,y) rem(g(x,y),s(z)) -> rem(x,z) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 0 1] [rem](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [0 0 0] [1 0 0] , [1 0 0] [1 0 1] [0] [f](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [0] [0 0 0] [0 0 0] [1], [1 0 0] [0] [s](x0) = [0 0 0]x0 + [0] [0 0 1] [1], [1 0 0] [1 0 0] [0] [g](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [0] [0 0 0] [0 0 0] [1], [1] [0] = [0] [0], [0] [nil] = [0] [1] orientation: [1 0 0] [1] [1 0 0] [0] f(x,nil()) = [0 0 0]x + [0] >= [0 0 0]x + [0] = g(nil(),x) [0 0 0] [1] [0 0 0] [1] [1 0 0] [1 0 0] [1] [1 0 0] [1 0 0] [0] rem(g(x,y),0()) = [0 0 0]x + [0 0 0]y + [0] >= [0 0 0]x + [0 0 0]y + [0] = g(x,y) [0 0 0] [0 0 0] [1] [0 0 0] [0 0 0] [1] [1 0 0] [1 0 0] [1 0 1] [1] [1 0 0] [1 0 1] rem(g(x,y),s(z)) = [0 0 0]x + [0 0 0]y + [0 0 0]z + [0] >= [0 0 0]x + [0 0 0]z = rem(x,z) [0 0 0] [0 0 0] [1 0 0] [0] [0 0 0] [1 0 0] problem: Qed