YES

Problem:
 d(x) -> e(u(x))
 d(u(x)) -> c(x)
 c(u(x)) -> b(x)
 v(e(x)) -> x
 b(u(x)) -> a(e(x))

Proof:
 Bounds Processor:
  bound: 0
  enrichment: match
  automaton:
   final states: {6,2,5,4,1}
   transitions:
    f70() -> 2*
    e0(2) -> 7*
    e0(3) -> 1*
    u0(2) -> 3*
    c0(2) -> 4*
    b0(2) -> 5*
    a0(7) -> 6*
    5 -> 4*
    6 -> 5*
  problem:
   
  Qed