YES Problem: b(f(b(x,z)),y) -> f(f(f(b(z,b(y,z))))) c(f(f(c(x,a(),z))),a(),y) -> b(y,f(b(a(),z))) b(b(c(b(a(),a()),a(),z),f(a())),y) -> z Proof: DP Processor: DPs: b#(f(b(x,z)),y) -> b#(y,z) b#(f(b(x,z)),y) -> b#(z,b(y,z)) c#(f(f(c(x,a(),z))),a(),y) -> b#(a(),z) c#(f(f(c(x,a(),z))),a(),y) -> b#(y,f(b(a(),z))) TRS: b(f(b(x,z)),y) -> f(f(f(b(z,b(y,z))))) c(f(f(c(x,a(),z))),a(),y) -> b(y,f(b(a(),z))) b(b(c(b(a(),a()),a(),z),f(a())),y) -> z TDG Processor: DPs: b#(f(b(x,z)),y) -> b#(y,z) b#(f(b(x,z)),y) -> b#(z,b(y,z)) c#(f(f(c(x,a(),z))),a(),y) -> b#(a(),z) c#(f(f(c(x,a(),z))),a(),y) -> b#(y,f(b(a(),z))) TRS: b(f(b(x,z)),y) -> f(f(f(b(z,b(y,z))))) c(f(f(c(x,a(),z))),a(),y) -> b(y,f(b(a(),z))) b(b(c(b(a(),a()),a(),z),f(a())),y) -> z graph: c#(f(f(c(x,a(),z))),a(),y) -> b#(a(),z) -> b#(f(b(x,z)),y) -> b#(z,b(y,z)) c#(f(f(c(x,a(),z))),a(),y) -> b#(a(),z) -> b#(f(b(x,z)),y) -> b#(y,z) c#(f(f(c(x,a(),z))),a(),y) -> b#(y,f(b(a(),z))) -> b#(f(b(x,z)),y) -> b#(z,b(y,z)) c#(f(f(c(x,a(),z))),a(),y) -> b#(y,f(b(a(),z))) -> b#(f(b(x,z)),y) -> b#(y,z) b#(f(b(x,z)),y) -> b#(z,b(y,z)) -> b#(f(b(x,z)),y) -> b#(z,b(y,z)) b#(f(b(x,z)),y) -> b#(z,b(y,z)) -> b#(f(b(x,z)),y) -> b#(y,z) b#(f(b(x,z)),y) -> b#(y,z) -> b#(f(b(x,z)),y) -> b#(z,b(y,z)) b#(f(b(x,z)),y) -> b#(y,z) -> b#(f(b(x,z)),y) -> b#(y,z) SCC Processor: #sccs: 1 #rules: 2 #arcs: 8/16 DPs: b#(f(b(x,z)),y) -> b#(y,z) b#(f(b(x,z)),y) -> b#(z,b(y,z)) TRS: b(f(b(x,z)),y) -> f(f(f(b(z,b(y,z))))) c(f(f(c(x,a(),z))),a(),y) -> b(y,f(b(a(),z))) b(b(c(b(a(),a()),a(),z),f(a())),y) -> z Usable Rule Processor: DPs: b#(f(b(x,z)),y) -> b#(y,z) b#(f(b(x,z)),y) -> b#(z,b(y,z)) TRS: b(f(b(x,z)),y) -> f(f(f(b(z,b(y,z))))) b(b(c(b(a(),a()),a(),z),f(a())),y) -> z Matrix Interpretation Processor: dim=2 usable rules: b(f(b(x,z)),y) -> f(f(f(b(z,b(y,z))))) b(b(c(b(a(),a()),a(),z),f(a())),y) -> z interpretation: [b#](x0, x1) = [2 0]x0 + [2 0]x1, [0 2] [2 2] [2] [c](x0, x1, x2) = [0 0]x0 + [0 1]x2 + [0], [0] [a] = [0], [0 1] [f](x0) = [0 0]x0, [1 0] [0 0] [0] [b](x0, x1) = [0 2]x0 + [1 0]x1 + [2] orientation: b#(f(b(x,z)),y) = [0 4]x + [2 0]y + [2 0]z + [4] >= [2 0]y + [2 0]z = b#(y,z) b#(f(b(x,z)),y) = [0 4]x + [2 0]y + [2 0]z + [4] >= [2 0]y + [2 0]z = b#(z,b(y,z)) [0 2] [0 0] [1 0] [2] [0] b(f(b(x,z)),y) = [0 0]x + [1 0]y + [0 0]z + [2] >= [0] = f(f(f(b(z,b(y,z))))) [0 0] [2 2] [6] b(b(c(b(a(),a()),a(),z),f(a())),y) = [1 0]y + [0 4]z + [6] >= z = z problem: DPs: TRS: b(f(b(x,z)),y) -> f(f(f(b(z,b(y,z))))) b(b(c(b(a(),a()),a(),z),f(a())),y) -> z Qed