YES

TRS:

  and(tt(),X) -> activate(X)
  plus(N,0()) -> N
  plus(N,s(M)) -> s(plus(N,M))
  activate(X) -> X

linear polynomial interpretations on N:

  and_A(x1,x2) = x1 + x2 + 1
  and#_A(x1,x2) = x1 + x2 + 1
  tt_A = 0
  tt#_A = 0
  activate_A(x1) = x1
  activate#_A(x1) = x1
  plus_A(x1,x2) = x1 + x2
  plus#_A(x1,x2) = x1 + x2
  0_A = 0
  0#_A = 0
  s_A(x1) = x1 + 1
  s#_A(x1) = x1 + 1

precedence:

  and = plus > tt = activate = 0 = s