YES

TRS:

  times(x,0()) -> 0()
  times(x,s(y)) -> plus(times(x,y),x)
  plus(x,0()) -> x
  plus(0(),x) -> x
  plus(x,s(y)) -> s(plus(x,y))
  plus(s(x),y) -> s(plus(x,y))

max/plus interpretations on N:

  times_A(x1,x2) = max{2, 1 + x1, 1 + x2}
  times#_A(x1,x2) = max{2, 1 + x1, 1 + x2}
  0_A = 0
  0#_A = 0
  s_A(x1) = max{0, x1}
  s#_A(x1) = max{0, x1}
  plus_A(x1,x2) = max{2, x1, x2}
  plus#_A(x1,x2) = max{2, x1, x2}

precedence:

  0 > times > plus > s