YES

TRS:

  f(x) -> s(x)
  f(s(s(x))) -> s(f(f(x)))

max/plus interpretations on N:

  f_A(x1) = max{2, 2 + x1}
  f#_A(x1) = max{2, 2 + x1}
  s_A(x1) = max{1, 2 + x1}
  s#_A(x1) = max{1, 2 + x1}

precedence:

  f > s