YES

TRS:

  app(id(),x) -> x
  app(plus(),0()) -> id()
  app(app(plus(),app(s(),x)),y) -> app(s(),app(app(plus(),x),y))

max/plus interpretations on N:

  app_A(x1,x2) = max{0, 3 + x1, x2}
  app#_A(x1,x2) = max{0, 3 + x1, x2}
  id_A = 1
  id#_A = 1
  plus_A = 2
  plus#_A = 2
  0_A = 2
  0#_A = 2
  s_A = 4
  s#_A = 4

precedence:

  app > 0 = s > plus > id