YES

TRS:

  f(s(x),y) -> f(x,s(s(x)))
  f(x,s(s(y))) -> f(y,x)

max/plus interpretations on N:

  f_A(x1,x2) = max{0, 2 + x1, 1 + x2}
  f#_A(x1,x2) = max{0, 2 + x1, 1 + x2}
  s_A(x1) = max{4, 1 + x1}
  s#_A(x1) = max{4, 1 + x1}

precedence:

  f > s