YES We show the termination of the TRS R: app(f(),|0|()) -> true() app(f(),|1|()) -> false() app(f(),app(s(),x)) -> app(f(),x) app(app(app(if(),true()),app(s(),x)),app(s(),y)) -> app(s(),x) app(app(app(if(),false()),app(s(),x)),app(s(),y)) -> app(s(),y) app(app(g(),x),app(c(),y)) -> app(c(),app(app(g(),x),y)) app(app(g(),x),app(c(),y)) -> app(app(g(),x),app(app(app(if(),app(f(),x)),app(c(),app(app(g(),app(s(),x)),y))),app(c(),y))) app(app(map(),|fun|),nil()) -> nil() app(app(map(),|fun|),app(app(cons(),x),xs)) -> app(app(cons(),app(|fun|,x)),app(app(map(),|fun|),xs)) app(app(filter(),|fun|),nil()) -> nil() app(app(filter(),|fun|),app(app(cons(),x),xs)) -> app(app(app(app(filter2(),app(|fun|,x)),|fun|),x),xs) app(app(app(app(filter2(),true()),|fun|),x),xs) -> app(app(cons(),x),app(app(filter(),|fun|),xs)) app(app(app(app(filter2(),false()),|fun|),x),xs) -> app(app(filter(),|fun|),xs) Instead we prove termination of the uncurried system: app(c_0(),y) -> c_1(y) app(cons_0(),y) -> cons_1(y) app(cons_1(x1),y) -> cons_2(x1,y) app(f_0(),y) -> f_1(y) app(filter_0(),y) -> filter_1(y) app(filter_1(x1),y) -> filter_2(x1,y) app(filter2_0(),y) -> filter2_1(y) app(filter2_1(x1),y) -> filter2_2(x1,y) app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) app(g_0(),y) -> g_1(y) app(g_1(x1),y) -> g_2(x1,y) app(if_0(),y) -> if_1(y) app(if_1(x1),y) -> if_2(x1,y) app(if_2(x1,x2),y) -> if_3(x1,x2,y) app(map_0(),y) -> map_1(y) app(map_1(x1),y) -> map_2(x1,y) app(s_0(),y) -> s_1(y) f_1(|0|_0()) -> true_0() f_1(|1|_0()) -> false_0() f_1(s_1(x)) -> f_1(x) if_3(true_0(),s_1(x),s_1(y)) -> s_1(x) if_3(false_0(),s_1(x),s_1(y)) -> s_1(y) g_2(x,c_1(y)) -> c_1(g_2(x,y)) g_2(x,c_1(y)) -> g_2(x,if_3(f_1(x),c_1(g_2(s_1(x),y)),c_1(y))) map_2(|fun|,nil_0()) -> nil_0() map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) filter_2(|fun|,nil_0()) -> nil_0() filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(f_0(),y) -> f_1#(y) p2: app#(filter_1(x1),y) -> filter_2#(x1,y) p3: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p4: app#(g_1(x1),y) -> g_2#(x1,y) p5: app#(if_2(x1,x2),y) -> if_3#(x1,x2,y) p6: app#(map_1(x1),y) -> map_2#(x1,y) p7: f_1#(s_1(x)) -> f_1#(x) p8: g_2#(x,c_1(y)) -> g_2#(x,y) p9: g_2#(x,c_1(y)) -> g_2#(x,if_3(f_1(x),c_1(g_2(s_1(x),y)),c_1(y))) p10: g_2#(x,c_1(y)) -> if_3#(f_1(x),c_1(g_2(s_1(x),y)),c_1(y)) p11: g_2#(x,c_1(y)) -> f_1#(x) p12: g_2#(x,c_1(y)) -> g_2#(s_1(x),y) p13: map_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p14: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) p15: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p16: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p17: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p18: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(c_0(),y) -> c_1(y) r2: app(cons_0(),y) -> cons_1(y) r3: app(cons_1(x1),y) -> cons_2(x1,y) r4: app(f_0(),y) -> f_1(y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(filter2_0(),y) -> filter2_1(y) r8: app(filter2_1(x1),y) -> filter2_2(x1,y) r9: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r10: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r11: app(g_0(),y) -> g_1(y) r12: app(g_1(x1),y) -> g_2(x1,y) r13: app(if_0(),y) -> if_1(y) r14: app(if_1(x1),y) -> if_2(x1,y) r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: app(s_0(),y) -> s_1(y) r19: f_1(|0|_0()) -> true_0() r20: f_1(|1|_0()) -> false_0() r21: f_1(s_1(x)) -> f_1(x) r22: if_3(true_0(),s_1(x),s_1(y)) -> s_1(x) r23: if_3(false_0(),s_1(x),s_1(y)) -> s_1(y) r24: g_2(x,c_1(y)) -> c_1(g_2(x,y)) r25: g_2(x,c_1(y)) -> g_2(x,if_3(f_1(x),c_1(g_2(s_1(x),y)),c_1(y))) r26: map_2(|fun|,nil_0()) -> nil_0() r27: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r28: filter_2(|fun|,nil_0()) -> nil_0() r29: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r30: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r31: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: {p2, p3, p6, p13, p14, p15, p16, p17, p18} {p8, p12} {p7} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p2: app#(map_1(x1),y) -> map_2#(x1,y) p3: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) p4: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p5: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p6: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p7: app#(filter_1(x1),y) -> filter_2#(x1,y) p8: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p9: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(c_0(),y) -> c_1(y) r2: app(cons_0(),y) -> cons_1(y) r3: app(cons_1(x1),y) -> cons_2(x1,y) r4: app(f_0(),y) -> f_1(y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(filter2_0(),y) -> filter2_1(y) r8: app(filter2_1(x1),y) -> filter2_2(x1,y) r9: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r10: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r11: app(g_0(),y) -> g_1(y) r12: app(g_1(x1),y) -> g_2(x1,y) r13: app(if_0(),y) -> if_1(y) r14: app(if_1(x1),y) -> if_2(x1,y) r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: app(s_0(),y) -> s_1(y) r19: f_1(|0|_0()) -> true_0() r20: f_1(|1|_0()) -> false_0() r21: f_1(s_1(x)) -> f_1(x) r22: if_3(true_0(),s_1(x),s_1(y)) -> s_1(x) r23: if_3(false_0(),s_1(x),s_1(y)) -> s_1(y) r24: g_2(x,c_1(y)) -> c_1(g_2(x,y)) r25: g_2(x,c_1(y)) -> g_2(x,if_3(f_1(x),c_1(g_2(s_1(x),y)),c_1(y))) r26: map_2(|fun|,nil_0()) -> nil_0() r27: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r28: filter_2(|fun|,nil_0()) -> nil_0() r29: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r30: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r31: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r28 Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: max/plus interpretation on natural numbers: map_2#_A(x1,x2) = max{x1 + 102, x2 - 1} cons_2_A(x1,x2) = max{x1 + 29, x2 + 32} app#_A(x1,x2) = max{x1 + 101, x2 + 27} map_1_A(x1) = max{56, x1 + 16} filter2_3_A(x1,x2,x3) = max{55, x1 - 100, x2 + 25} filter2_4#_A(x1,x2,x3,x4) = max{x2 + 125, x4 + 27} false_0_A = 25 filter_2#_A(x1,x2) = max{x1 + 125, x2 + 27} filter_1_A(x1) = x1 + 24 app_A(x1,x2) = max{55, x1 + 11} true_0_A = 25 filter_2_A(x1,x2) = max{34, x1 - 33, x2 - 31} nil_0_A = 30 base order 2: marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: map_2#_A(x1,x2) = x1 + x2 cons_2_A(x1,x2) = x1 + x2 + 5 app#_A(x1,x2) = x1 + x2 map_1_A(x1) = x1 + 3 filter2_3_A(x1,x2,x3) = x1 + x2 + x3 + 11 filter2_4#_A(x1,x2,x3,x4) = x2 + x4 + 3 false_0_A() = 10 filter_2#_A(x1,x2) = x1 + x2 + 3 filter_1_A(x1) = x1 + 3 app_A(x1,x2) = x1 + x2 + 1 true_0_A() = 10 filter_2_A(x1,x2) = x1 + x2 + 19 nil_0_A() = 7 map_2#!_A(x1,x2) = 10 cons_2!_A(x1,x2) = x1 + x2 app#!_A(x1,x2) = x1 + x2 + 8 map_1!_A(x1) = 9 filter2_3!_A(x1,x2,x3) = 5 filter2_4#!_A(x1,x2,x3,x4) = x2 + x4 + 6 false_0!_A() = 11 filter_2#!_A(x1,x2) = x1 + x2 + 2 filter_1!_A(x1) = 9 app!_A(x1,x2) = x1 + x2 + 7 true_0!_A() = 0 filter_2!_A(x1,x2) = x2 + 12 nil_0!_A() = 20 partial status: pi(map_2#) = [] pi(cons_2) = [1] pi(app#) = [1] pi(map_1) = [1] pi(filter2_3) = [2] pi(filter2_4#) = [] pi(false_0) = [] pi(filter_2#) = [1, 2] pi(filter_1) = [] pi(app) = [1] pi(true_0) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p1, p2, p4, p5, p6, p7, p8, p9 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) and R consists of: r1: app(c_0(),y) -> c_1(y) r2: app(cons_0(),y) -> cons_1(y) r3: app(cons_1(x1),y) -> cons_2(x1,y) r4: app(f_0(),y) -> f_1(y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(filter2_0(),y) -> filter2_1(y) r8: app(filter2_1(x1),y) -> filter2_2(x1,y) r9: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r10: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r11: app(g_0(),y) -> g_1(y) r12: app(g_1(x1),y) -> g_2(x1,y) r13: app(if_0(),y) -> if_1(y) r14: app(if_1(x1),y) -> if_2(x1,y) r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: app(s_0(),y) -> s_1(y) r19: f_1(|0|_0()) -> true_0() r20: f_1(|1|_0()) -> false_0() r21: f_1(s_1(x)) -> f_1(x) r22: if_3(true_0(),s_1(x),s_1(y)) -> s_1(x) r23: if_3(false_0(),s_1(x),s_1(y)) -> s_1(y) r24: g_2(x,c_1(y)) -> c_1(g_2(x,y)) r25: g_2(x,c_1(y)) -> g_2(x,if_3(f_1(x),c_1(g_2(s_1(x),y)),c_1(y))) r26: map_2(|fun|,nil_0()) -> nil_0() r27: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r28: filter_2(|fun|,nil_0()) -> nil_0() r29: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r30: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r31: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: {p1} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) and R consists of: r1: app(c_0(),y) -> c_1(y) r2: app(cons_0(),y) -> cons_1(y) r3: app(cons_1(x1),y) -> cons_2(x1,y) r4: app(f_0(),y) -> f_1(y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(filter2_0(),y) -> filter2_1(y) r8: app(filter2_1(x1),y) -> filter2_2(x1,y) r9: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r10: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r11: app(g_0(),y) -> g_1(y) r12: app(g_1(x1),y) -> g_2(x1,y) r13: app(if_0(),y) -> if_1(y) r14: app(if_1(x1),y) -> if_2(x1,y) r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: app(s_0(),y) -> s_1(y) r19: f_1(|0|_0()) -> true_0() r20: f_1(|1|_0()) -> false_0() r21: f_1(s_1(x)) -> f_1(x) r22: if_3(true_0(),s_1(x),s_1(y)) -> s_1(x) r23: if_3(false_0(),s_1(x),s_1(y)) -> s_1(y) r24: g_2(x,c_1(y)) -> c_1(g_2(x,y)) r25: g_2(x,c_1(y)) -> g_2(x,if_3(f_1(x),c_1(g_2(s_1(x),y)),c_1(y))) r26: map_2(|fun|,nil_0()) -> nil_0() r27: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r28: filter_2(|fun|,nil_0()) -> nil_0() r29: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r30: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r31: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r28 Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: max/plus interpretation on natural numbers: map_2#_A(x1,x2) = 0 cons_2_A(x1,x2) = max{5, x2 - 17} filter_2_A(x1,x2) = max{19, x1 - 16, x2 + 8} nil_0_A = 20 base order 2: marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: map_2#_A(x1,x2) = x2 cons_2_A(x1,x2) = x1 + x2 + 6 filter_2_A(x1,x2) = x1 + x2 + 10 nil_0_A() = 7 map_2#!_A(x1,x2) = x2 cons_2!_A(x1,x2) = x2 + 2 filter_2!_A(x1,x2) = x2 + 4 nil_0!_A() = 0 partial status: pi(map_2#) = [] pi(cons_2) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p1 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: g_2#(x,c_1(y)) -> g_2#(s_1(x),y) p2: g_2#(x,c_1(y)) -> g_2#(x,y) and R consists of: r1: app(c_0(),y) -> c_1(y) r2: app(cons_0(),y) -> cons_1(y) r3: app(cons_1(x1),y) -> cons_2(x1,y) r4: app(f_0(),y) -> f_1(y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(filter2_0(),y) -> filter2_1(y) r8: app(filter2_1(x1),y) -> filter2_2(x1,y) r9: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r10: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r11: app(g_0(),y) -> g_1(y) r12: app(g_1(x1),y) -> g_2(x1,y) r13: app(if_0(),y) -> if_1(y) r14: app(if_1(x1),y) -> if_2(x1,y) r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: app(s_0(),y) -> s_1(y) r19: f_1(|0|_0()) -> true_0() r20: f_1(|1|_0()) -> false_0() r21: f_1(s_1(x)) -> f_1(x) r22: if_3(true_0(),s_1(x),s_1(y)) -> s_1(x) r23: if_3(false_0(),s_1(x),s_1(y)) -> s_1(y) r24: g_2(x,c_1(y)) -> c_1(g_2(x,y)) r25: g_2(x,c_1(y)) -> g_2(x,if_3(f_1(x),c_1(g_2(s_1(x),y)),c_1(y))) r26: map_2(|fun|,nil_0()) -> nil_0() r27: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r28: filter_2(|fun|,nil_0()) -> nil_0() r29: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r30: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r31: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r28 Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: max/plus interpretation on natural numbers: g_2#_A(x1,x2) = max{0, x1 - 1} c_1_A(x1) = max{8, x1 - 9} s_1_A(x1) = max{0, x1 - 9} filter_2_A(x1,x2) = 15 nil_0_A = 14 base order 2: marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: g_2#_A(x1,x2) = x1 + x2 c_1_A(x1) = x1 + 5 s_1_A(x1) = x1 + 4 filter_2_A(x1,x2) = x2 + 19 nil_0_A() = 16 g_2#!_A(x1,x2) = x1 + x2 + 11 c_1!_A(x1) = x1 + 1 s_1!_A(x1) = x1 + 15 filter_2!_A(x1,x2) = 18 nil_0!_A() = 0 partial status: pi(g_2#) = [] pi(c_1) = [] pi(s_1) = [] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p1, p2 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: f_1#(s_1(x)) -> f_1#(x) and R consists of: r1: app(c_0(),y) -> c_1(y) r2: app(cons_0(),y) -> cons_1(y) r3: app(cons_1(x1),y) -> cons_2(x1,y) r4: app(f_0(),y) -> f_1(y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(filter2_0(),y) -> filter2_1(y) r8: app(filter2_1(x1),y) -> filter2_2(x1,y) r9: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r10: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r11: app(g_0(),y) -> g_1(y) r12: app(g_1(x1),y) -> g_2(x1,y) r13: app(if_0(),y) -> if_1(y) r14: app(if_1(x1),y) -> if_2(x1,y) r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: app(s_0(),y) -> s_1(y) r19: f_1(|0|_0()) -> true_0() r20: f_1(|1|_0()) -> false_0() r21: f_1(s_1(x)) -> f_1(x) r22: if_3(true_0(),s_1(x),s_1(y)) -> s_1(x) r23: if_3(false_0(),s_1(x),s_1(y)) -> s_1(y) r24: g_2(x,c_1(y)) -> c_1(g_2(x,y)) r25: g_2(x,c_1(y)) -> g_2(x,if_3(f_1(x),c_1(g_2(s_1(x),y)),c_1(y))) r26: map_2(|fun|,nil_0()) -> nil_0() r27: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r28: filter_2(|fun|,nil_0()) -> nil_0() r29: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r30: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r31: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r28 Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: max/plus interpretation on natural numbers: f_1#_A(x1) = x1 + 7 s_1_A(x1) = x1 + 6 filter_2_A(x1,x2) = 3 nil_0_A = 2 base order 2: marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: f_1#_A(x1) = x1 s_1_A(x1) = x1 + 11 filter_2_A(x1,x2) = x2 + 14 nil_0_A() = 16 f_1#!_A(x1) = x1 s_1!_A(x1) = x1 + 15 filter_2!_A(x1,x2) = x2 + 1 nil_0!_A() = 0 partial status: pi(f_1#) = [] pi(s_1) = [1] pi(filter_2) = [] pi(nil_0) = [] The following rules are removed: p1 Then no dependency pair remains.