YES
We show the termination of the TRS R:

  app(app(minus(),x),|0|()) -> x
  app(app(minus(),app(s(),x)),app(s(),y)) -> app(app(minus(),x),y)
  app(f(),|0|()) -> app(s(),|0|())
  app(f(),app(s(),x)) -> app(app(minus(),app(s(),x)),app(g(),app(f(),x)))
  app(g(),|0|()) -> |0|()
  app(g(),app(s(),x)) -> app(app(minus(),app(s(),x)),app(f(),app(g(),x)))
  app(app(map(),|fun|),nil()) -> nil()
  app(app(map(),|fun|),app(app(cons(),x),xs)) -> app(app(cons(),app(|fun|,x)),app(app(map(),|fun|),xs))
  app(app(filter(),|fun|),nil()) -> nil()
  app(app(filter(),|fun|),app(app(cons(),x),xs)) -> app(app(app(app(filter2(),app(|fun|,x)),|fun|),x),xs)
  app(app(app(app(filter2(),true()),|fun|),x),xs) -> app(app(cons(),x),app(app(filter(),|fun|),xs))
  app(app(app(app(filter2(),false()),|fun|),x),xs) -> app(app(filter(),|fun|),xs)

Instead we prove termination of the uncurried system:

  app(cons_0(),y) -> cons_1(y)
  app(cons_1(x1),y) -> cons_2(x1,y)
  app(f_0(),y) -> f_1(y)
  app(filter_0(),y) -> filter_1(y)
  app(filter_1(x1),y) -> filter_2(x1,y)
  app(filter2_0(),y) -> filter2_1(y)
  app(filter2_1(x1),y) -> filter2_2(x1,y)
  app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
  app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
  app(g_0(),y) -> g_1(y)
  app(map_0(),y) -> map_1(y)
  app(map_1(x1),y) -> map_2(x1,y)
  app(minus_0(),y) -> minus_1(y)
  app(minus_1(x1),y) -> minus_2(x1,y)
  app(s_0(),y) -> s_1(y)
  minus_2(x,|0|_0()) -> x
  minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
  f_1(|0|_0()) -> s_1(|0|_0())
  f_1(s_1(x)) -> minus_2(s_1(x),g_1(f_1(x)))
  g_1(|0|_0()) -> |0|_0()
  g_1(s_1(x)) -> minus_2(s_1(x),f_1(g_1(x)))
  map_2(|fun|,nil_0()) -> nil_0()
  map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs))
  filter_2(|fun|,nil_0()) -> nil_0()
  filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs)
  filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs))
  filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs)


-- SCC decomposition.

Consider the dependency pair problem (P, R), where P consists of

p1: app#(f_0(),y) -> f_1#(y)
p2: app#(filter_1(x1),y) -> filter_2#(x1,y)
p3: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y)
p4: app#(g_0(),y) -> g_1#(y)
p5: app#(map_1(x1),y) -> map_2#(x1,y)
p6: app#(minus_1(x1),y) -> minus_2#(x1,y)
p7: minus_2#(s_1(x),s_1(y)) -> minus_2#(x,y)
p8: f_1#(s_1(x)) -> minus_2#(s_1(x),g_1(f_1(x)))
p9: f_1#(s_1(x)) -> g_1#(f_1(x))
p10: f_1#(s_1(x)) -> f_1#(x)
p11: g_1#(s_1(x)) -> minus_2#(s_1(x),f_1(g_1(x)))
p12: g_1#(s_1(x)) -> f_1#(g_1(x))
p13: g_1#(s_1(x)) -> g_1#(x)
p14: map_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x)
p15: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs)
p16: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs)
p17: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x)
p18: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs)
p19: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(f_0(),y) -> f_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(g_0(),y) -> g_1(y)
r11: app(map_0(),y) -> map_1(y)
r12: app(map_1(x1),y) -> map_2(x1,y)
r13: app(minus_0(),y) -> minus_1(y)
r14: app(minus_1(x1),y) -> minus_2(x1,y)
r15: app(s_0(),y) -> s_1(y)
r16: minus_2(x,|0|_0()) -> x
r17: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r18: f_1(|0|_0()) -> s_1(|0|_0())
r19: f_1(s_1(x)) -> minus_2(s_1(x),g_1(f_1(x)))
r20: g_1(|0|_0()) -> |0|_0()
r21: g_1(s_1(x)) -> minus_2(s_1(x),f_1(g_1(x)))
r22: map_2(|fun|,nil_0()) -> nil_0()
r23: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs))
r24: filter_2(|fun|,nil_0()) -> nil_0()
r25: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs)
r26: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs))
r27: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs)

The estimated dependency graph contains the following SCCs:

  {p2, p3, p5, p14, p15, p16, p17, p18, p19}
  {p9, p10, p12, p13}
  {p7}


-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: map_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x)
p2: app#(map_1(x1),y) -> map_2#(x1,y)
p3: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs)
p4: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y)
p5: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs)
p6: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x)
p7: app#(filter_1(x1),y) -> filter_2#(x1,y)
p8: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs)
p9: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(f_0(),y) -> f_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(g_0(),y) -> g_1(y)
r11: app(map_0(),y) -> map_1(y)
r12: app(map_1(x1),y) -> map_2(x1,y)
r13: app(minus_0(),y) -> minus_1(y)
r14: app(minus_1(x1),y) -> minus_2(x1,y)
r15: app(s_0(),y) -> s_1(y)
r16: minus_2(x,|0|_0()) -> x
r17: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r18: f_1(|0|_0()) -> s_1(|0|_0())
r19: f_1(s_1(x)) -> minus_2(s_1(x),g_1(f_1(x)))
r20: g_1(|0|_0()) -> |0|_0()
r21: g_1(s_1(x)) -> minus_2(s_1(x),f_1(g_1(x)))
r22: map_2(|fun|,nil_0()) -> nil_0()
r23: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs))
r24: filter_2(|fun|,nil_0()) -> nil_0()
r25: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs)
r26: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs))
r27: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs)

The set of usable rules consists of

  r24, r25, r26, r27

Take the reduction pair:

  generalized weighted path order (>=MG, >G)
  
    base order 1:
  
      max/plus interpretation on natural numbers:
      
        map_2#_A(x1,x2) = max{1, x1 - 23, x2 - 18}
        cons_2_A(x1,x2) = max{x1 + 59, x2 + 20}
        app#_A(x1,x2) = max{41, x1 - 23, x2 - 2}
        map_1_A(x1) = x1 + 23
        filter2_3_A(x1,x2,x3) = max{x1 + 83, x2 + 23}
        filter2_4#_A(x1,x2,x3,x4) = max{60, x2, x4 - 60}
        false_0_A = 59
        filter_2#_A(x1,x2) = max{60, x1, x2 - 60}
        filter_1_A(x1) = max{83, x1 + 23}
        app_A(x1,x2) = max{22, x2 + 16}
        true_0_A = 17
        filter_2_A(x1,x2) = max{84, x2 + 45}
        nil_0_A = 1
        filter2_4_A(x1,x2,x3,x4) = max{104, x3 + 59, x4 + 65}
  
    base order 2:
  
      marked-algebra reduction triple (>=A, >=A!, >A!):
      
        max/plus interpretation on natural numbers:
        
          map_2#_A(x1,x2) = max{1, x1 - 22}
          cons_2_A(x1,x2) = max{1, x2 - 2}
          app#_A(x1,x2) = max{1, x1 - 22}
          map_1_A(x1) = max{21, x1 + 13}
          filter2_3_A(x1,x2,x3) = max{21, x1 + 13, x2 + 14, x3 + 19}
          filter2_4#_A(x1,x2,x3,x4) = max{1, x2 - 22}
          false_0_A = 19
          filter_2#_A(x1,x2) = max{1, x1 - 22}
          filter_1_A(x1) = x1 + 13
          app_A(x1,x2) = x2 + 10
          true_0_A = 19
          filter_2_A(x1,x2) = x1 + 12
          nil_0_A = 12
          filter2_4_A(x1,x2,x3,x4) = x2 + 12
          map_2#!_A(x1,x2) = x1 + 3
          cons_2!_A(x1,x2) = 0
          app#!_A(x1,x2) = 1
          map_1!_A(x1) = max{18, x1 - 24}
          filter2_3!_A(x1,x2,x3) = max{0, x1 - 16, x2 - 2, x3 - 1}
          filter2_4#!_A(x1,x2,x3,x4) = 0
          false_0!_A = 0
          filter_2#!_A(x1,x2) = 0
          filter_1!_A(x1) = max{21, x1 + 18}
          app!_A(x1,x2) = max{20, x1 - 35, x2 + 17}
          true_0!_A = 1
          filter_2!_A(x1,x2) = 0
          nil_0!_A = 0
          filter2_4!_A(x1,x2,x3,x4) = 0
  
    partial status:
  
      pi(map_2#) = []
      pi(cons_2) = []
      pi(app#) = []
      pi(map_1) = []
      pi(filter2_3) = [1]
      pi(filter2_4#) = []
      pi(false_0) = []
      pi(filter_2#) = []
      pi(filter_1) = [1]
      pi(app) = []
      pi(true_0) = []
      pi(filter_2) = []
      pi(nil_0) = []
      pi(filter2_4) = []

The following rules are removed:

  p1, p2, p4, p6, p7



-- SCC decomposition.

Consider the dependency pair problem (P, R), where P consists of

p1: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs)
p2: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs)
p3: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs)
p4: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(f_0(),y) -> f_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(g_0(),y) -> g_1(y)
r11: app(map_0(),y) -> map_1(y)
r12: app(map_1(x1),y) -> map_2(x1,y)
r13: app(minus_0(),y) -> minus_1(y)
r14: app(minus_1(x1),y) -> minus_2(x1,y)
r15: app(s_0(),y) -> s_1(y)
r16: minus_2(x,|0|_0()) -> x
r17: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r18: f_1(|0|_0()) -> s_1(|0|_0())
r19: f_1(s_1(x)) -> minus_2(s_1(x),g_1(f_1(x)))
r20: g_1(|0|_0()) -> |0|_0()
r21: g_1(s_1(x)) -> minus_2(s_1(x),f_1(g_1(x)))
r22: map_2(|fun|,nil_0()) -> nil_0()
r23: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs))
r24: filter_2(|fun|,nil_0()) -> nil_0()
r25: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs)
r26: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs))
r27: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs)

The estimated dependency graph contains the following SCCs:

  {p1}
  {p2, p3, p4}


-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(f_0(),y) -> f_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(g_0(),y) -> g_1(y)
r11: app(map_0(),y) -> map_1(y)
r12: app(map_1(x1),y) -> map_2(x1,y)
r13: app(minus_0(),y) -> minus_1(y)
r14: app(minus_1(x1),y) -> minus_2(x1,y)
r15: app(s_0(),y) -> s_1(y)
r16: minus_2(x,|0|_0()) -> x
r17: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r18: f_1(|0|_0()) -> s_1(|0|_0())
r19: f_1(s_1(x)) -> minus_2(s_1(x),g_1(f_1(x)))
r20: g_1(|0|_0()) -> |0|_0()
r21: g_1(s_1(x)) -> minus_2(s_1(x),f_1(g_1(x)))
r22: map_2(|fun|,nil_0()) -> nil_0()
r23: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs))
r24: filter_2(|fun|,nil_0()) -> nil_0()
r25: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs)
r26: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs))
r27: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs)

The set of usable rules consists of

  (no rules)

Take the reduction pair:

  generalized weighted path order (>=MG, >G)
  
    base order 1:
  
      max/plus interpretation on natural numbers:
      
        map_2#_A(x1,x2) = max{23, x2 + 11}
        cons_2_A(x1,x2) = max{26, x1 - 10, x2 + 12}
  
    base order 2:
  
      marked-algebra reduction triple (>=A, >=A!, >A!):
      
        max/plus interpretation on natural numbers:
        
          map_2#_A(x1,x2) = 0
          cons_2_A(x1,x2) = max{7, x1 - 8, x2 - 8}
          map_2#!_A(x1,x2) = x1 + 4
          cons_2!_A(x1,x2) = max{2, x1 - 62, x2 - 8}
  
    partial status:
  
      pi(map_2#) = [2]
      pi(cons_2) = []

The following rules are removed:

  p1

Then no dependency pair remains.

-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs)
p2: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs)
p3: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(f_0(),y) -> f_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(g_0(),y) -> g_1(y)
r11: app(map_0(),y) -> map_1(y)
r12: app(map_1(x1),y) -> map_2(x1,y)
r13: app(minus_0(),y) -> minus_1(y)
r14: app(minus_1(x1),y) -> minus_2(x1,y)
r15: app(s_0(),y) -> s_1(y)
r16: minus_2(x,|0|_0()) -> x
r17: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r18: f_1(|0|_0()) -> s_1(|0|_0())
r19: f_1(s_1(x)) -> minus_2(s_1(x),g_1(f_1(x)))
r20: g_1(|0|_0()) -> |0|_0()
r21: g_1(s_1(x)) -> minus_2(s_1(x),f_1(g_1(x)))
r22: map_2(|fun|,nil_0()) -> nil_0()
r23: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs))
r24: filter_2(|fun|,nil_0()) -> nil_0()
r25: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs)
r26: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs))
r27: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs)

The set of usable rules consists of

  r1, r2, r4, r6, r7, r8, r11, r13, r14, r15, r16, r17, r18, r20, r22, r24

Take the reduction pair:

  generalized weighted path order (>=MG, >G)
  
    base order 1:
  
      max/plus interpretation on natural numbers:
      
        filter2_4#_A(x1,x2,x3,x4) = max{100, x3 + 64, x4 + 63}
        false_0_A = 29
        filter_2#_A(x1,x2) = max{100, x2 + 63}
        cons_2_A(x1,x2) = max{36, x1 + 1, x2}
        app_A(x1,x2) = max{62, x1 - 3, x2 + 28}
        true_0_A = 48
        cons_0_A = 1
        cons_1_A(x1) = x1 + 4
        filter_0_A = 1
        filter_1_A(x1) = x1 + 27
        filter2_0_A = 2
        filter2_1_A(x1) = max{1, x1 - 1}
        filter2_2_A(x1,x2) = max{x1 - 5, x2 + 27}
        filter2_3_A(x1,x2,x3) = max{29, x1 - 9, x2 + 22, x3 + 27}
        map_0_A = 2
        map_1_A(x1) = x1 + 2
        minus_0_A = 1
        minus_1_A(x1) = x1 + 9
        minus_2_A(x1,x2) = max{33, x1 + 5, x2 - 66}
        s_0_A = 1
        s_1_A(x1) = max{29, x1 + 27}
        |0|_0_A = 34
        f_1_A(x1) = max{62, x1 - 4}
        g_1_A(x1) = max{33, x1 + 3}
        map_2_A(x1,x2) = max{30, x1 - 1, x2 + 28}
        nil_0_A = 50
        filter_2_A(x1,x2) = max{49, x1 + 18, x2 + 15}
  
    base order 2:
  
      marked-algebra reduction triple (>=A, >=A!, >A!):
      
        max/plus interpretation on natural numbers:
        
          filter2_4#_A(x1,x2,x3,x4) = max{1, x2 - 1, x3 - 55, x4 - 58}
          false_0_A = 71
          filter_2#_A(x1,x2) = max{1, x1 - 1, x2 - 58}
          cons_2_A(x1,x2) = max{57, x1 + 3, x2}
          app_A(x1,x2) = max{71, x1 - 5, x2 + 17}
          true_0_A = 71
          cons_0_A = 10
          cons_1_A(x1) = x1 + 10
          filter_0_A = 5
          filter_1_A(x1) = max{5, x1 + 4}
          filter2_0_A = 5
          filter2_1_A(x1) = max{5, x1 + 4}
          filter2_2_A(x1,x2) = max{5, x1 - 1, x2 + 4}
          filter2_3_A(x1,x2,x3) = max{x1 - 6, x2 - 1, x3 + 8}
          map_0_A = 5
          map_1_A(x1) = max{5, x1 + 4}
          minus_0_A = 5
          minus_1_A(x1) = x1 + 8
          minus_2_A(x1,x2) = max{53, x1 + 3, x2 - 35}
          s_0_A = 5
          s_1_A(x1) = max{36, x1 + 17}
          |0|_0_A = 19
          f_1_A(x1) = max{71, x1 + 16}
          g_1_A(x1) = max{18, x1 + 17}
          map_2_A(x1,x2) = max{56, x1 - 2, x2 + 17}
          nil_0_A = 62
          filter_2_A(x1,x2) = max{61, x1 - 6, x2 + 3}
          filter2_4#!_A(x1,x2,x3,x4) = max{x2 + 26, x3 - 1, x4 + 19}
          false_0!_A = 27
          filter_2#!_A(x1,x2) = max{x1 + 26, x2 + 19}
          cons_2!_A(x1,x2) = 0
          app!_A(x1,x2) = max{25, x1 - 9, x2 + 23}
          true_0!_A = 27
          cons_0!_A = 27
          cons_1!_A(x1) = max{26, x1 - 1}
          filter_0!_A = 1
          filter_1!_A(x1) = max{0, x1 - 1}
          filter2_0!_A = 2
          filter2_1!_A(x1) = max{1, x1 - 5}
          filter2_2!_A(x1,x2) = max{26, x1 - 4, x2 - 6}
          filter2_3!_A(x1,x2,x3) = max{27, x1 - 3, x2 - 6, x3 - 1}
          map_0!_A = 1
          map_1!_A(x1) = max{24, x1 - 6}
          minus_0!_A = 1
          minus_1!_A(x1) = max{2, x1 - 184}
          minus_2!_A(x1,x2) = max{3, x1 - 183, x2 - 89}
          s_0!_A = 1
          s_1!_A(x1) = max{22, x1 - 54}
          |0|_0!_A = 0
          f_1!_A(x1) = max{21, x1 - 108}
          g_1!_A(x1) = max{1, x1 - 163}
          map_2!_A(x1,x2) = 1
          nil_0!_A = 0
          filter_2!_A(x1,x2) = 28
  
    partial status:
  
      pi(filter2_4#) = [4]
      pi(false_0) = []
      pi(filter_2#) = [2]
      pi(cons_2) = [2]
      pi(app) = []
      pi(true_0) = []
      pi(cons_0) = []
      pi(cons_1) = [1]
      pi(filter_0) = []
      pi(filter_1) = []
      pi(filter2_0) = []
      pi(filter2_1) = []
      pi(filter2_2) = []
      pi(filter2_3) = [3]
      pi(map_0) = []
      pi(map_1) = [1]
      pi(minus_0) = []
      pi(minus_1) = [1]
      pi(minus_2) = []
      pi(s_0) = []
      pi(s_1) = [1]
      pi(|0|_0) = []
      pi(f_1) = []
      pi(g_1) = [1]
      pi(map_2) = [2]
      pi(nil_0) = []
      pi(filter_2) = [1, 2]

The following rules are removed:

  p2



-- SCC decomposition.

Consider the dependency pair problem (P, R), where P consists of

p1: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs)
p2: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(f_0(),y) -> f_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(g_0(),y) -> g_1(y)
r11: app(map_0(),y) -> map_1(y)
r12: app(map_1(x1),y) -> map_2(x1,y)
r13: app(minus_0(),y) -> minus_1(y)
r14: app(minus_1(x1),y) -> minus_2(x1,y)
r15: app(s_0(),y) -> s_1(y)
r16: minus_2(x,|0|_0()) -> x
r17: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r18: f_1(|0|_0()) -> s_1(|0|_0())
r19: f_1(s_1(x)) -> minus_2(s_1(x),g_1(f_1(x)))
r20: g_1(|0|_0()) -> |0|_0()
r21: g_1(s_1(x)) -> minus_2(s_1(x),f_1(g_1(x)))
r22: map_2(|fun|,nil_0()) -> nil_0()
r23: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs))
r24: filter_2(|fun|,nil_0()) -> nil_0()
r25: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs)
r26: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs))
r27: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs)

The estimated dependency graph contains the following SCCs:

  (no SCCs)

-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: g_1#(s_1(x)) -> f_1#(g_1(x))
p2: f_1#(s_1(x)) -> f_1#(x)
p3: f_1#(s_1(x)) -> g_1#(f_1(x))
p4: g_1#(s_1(x)) -> g_1#(x)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(f_0(),y) -> f_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(g_0(),y) -> g_1(y)
r11: app(map_0(),y) -> map_1(y)
r12: app(map_1(x1),y) -> map_2(x1,y)
r13: app(minus_0(),y) -> minus_1(y)
r14: app(minus_1(x1),y) -> minus_2(x1,y)
r15: app(s_0(),y) -> s_1(y)
r16: minus_2(x,|0|_0()) -> x
r17: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r18: f_1(|0|_0()) -> s_1(|0|_0())
r19: f_1(s_1(x)) -> minus_2(s_1(x),g_1(f_1(x)))
r20: g_1(|0|_0()) -> |0|_0()
r21: g_1(s_1(x)) -> minus_2(s_1(x),f_1(g_1(x)))
r22: map_2(|fun|,nil_0()) -> nil_0()
r23: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs))
r24: filter_2(|fun|,nil_0()) -> nil_0()
r25: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs)
r26: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs))
r27: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs)

The set of usable rules consists of

  r16, r17, r18, r19, r20, r21

Take the reduction pair:

  generalized weighted path order (>=MG, >G)
  
    base order 1:
  
      max/plus interpretation on natural numbers:
      
        g_1#_A(x1) = max{1, x1 - 15}
        s_1_A(x1) = max{17, x1 + 6}
        f_1#_A(x1) = max{2, x1 - 13}
        g_1_A(x1) = max{5, x1 + 4}
        f_1_A(x1) = max{14, x1 + 6}
        minus_2_A(x1,x2) = max{13, x1 + 3, x2 - 85}
        |0|_0_A = 16
  
    base order 2:
  
      marked-algebra reduction triple (>=A, >=A!, >A!):
      
        max/plus interpretation on natural numbers:
        
          g_1#_A(x1) = max{0, x1 - 40}
          s_1_A(x1) = max{26, x1 + 24}
          f_1#_A(x1) = max{0, x1 - 32}
          g_1_A(x1) = max{31, x1 + 11}
          f_1_A(x1) = max{39, x1 + 10}
          minus_2_A(x1,x2) = max{37, x1 + 10, x2 - 51}
          |0|_0_A = 15
          g_1#!_A(x1) = max{2, x1 - 51}
          s_1!_A(x1) = max{4, x1 - 40}
          f_1#!_A(x1) = max{1, x1 - 39}
          g_1!_A(x1) = max{6, x1 - 40}
          f_1!_A(x1) = max{5, x1 - 48}
          minus_2!_A(x1,x2) = max{6, x1 - 64, x2 - 56}
          |0|_0!_A = 3
  
    partial status:
  
      pi(g_1#) = []
      pi(s_1) = [1]
      pi(f_1#) = []
      pi(g_1) = [1]
      pi(f_1) = []
      pi(minus_2) = []
      pi(|0|_0) = []

The following rules are removed:

  p1, p2, p3, p4

Then no dependency pair remains.

-- Reduction pair.

Consider the dependency pair problem (P, R), where P consists of

p1: minus_2#(s_1(x),s_1(y)) -> minus_2#(x,y)

and R consists of:

r1: app(cons_0(),y) -> cons_1(y)
r2: app(cons_1(x1),y) -> cons_2(x1,y)
r3: app(f_0(),y) -> f_1(y)
r4: app(filter_0(),y) -> filter_1(y)
r5: app(filter_1(x1),y) -> filter_2(x1,y)
r6: app(filter2_0(),y) -> filter2_1(y)
r7: app(filter2_1(x1),y) -> filter2_2(x1,y)
r8: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y)
r9: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y)
r10: app(g_0(),y) -> g_1(y)
r11: app(map_0(),y) -> map_1(y)
r12: app(map_1(x1),y) -> map_2(x1,y)
r13: app(minus_0(),y) -> minus_1(y)
r14: app(minus_1(x1),y) -> minus_2(x1,y)
r15: app(s_0(),y) -> s_1(y)
r16: minus_2(x,|0|_0()) -> x
r17: minus_2(s_1(x),s_1(y)) -> minus_2(x,y)
r18: f_1(|0|_0()) -> s_1(|0|_0())
r19: f_1(s_1(x)) -> minus_2(s_1(x),g_1(f_1(x)))
r20: g_1(|0|_0()) -> |0|_0()
r21: g_1(s_1(x)) -> minus_2(s_1(x),f_1(g_1(x)))
r22: map_2(|fun|,nil_0()) -> nil_0()
r23: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs))
r24: filter_2(|fun|,nil_0()) -> nil_0()
r25: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs)
r26: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs))
r27: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs)

The set of usable rules consists of

  (no rules)

Take the reduction pair:

  generalized weighted path order (>=MG, >G)
  
    base order 1:
  
      max/plus interpretation on natural numbers:
      
        minus_2#_A(x1,x2) = x2 + 41
        s_1_A(x1) = x1 + 42
  
    base order 2:
  
      marked-algebra reduction triple (>=A, >=A!, >A!):
      
        max/plus interpretation on natural numbers:
        
          minus_2#_A(x1,x2) = 0
          s_1_A(x1) = max{8, x1 - 24}
          minus_2#!_A(x1,x2) = x2 + 26
          s_1!_A(x1) = x1 + 27
  
    partial status:
  
      pi(minus_2#) = [2]
      pi(s_1) = [1]

The following rules are removed:

  p1

Then no dependency pair remains.