YES We show the termination of the TRS R: app(app(le(),|0|()),y) -> true() app(app(le(),app(s(),x)),|0|()) -> false() app(app(le(),app(s(),x)),app(s(),y)) -> app(app(le(),x),y) app(pred(),app(s(),x)) -> x app(app(minus(),x),|0|()) -> x app(app(minus(),x),app(s(),y)) -> app(pred(),app(app(minus(),x),y)) app(app(gcd(),|0|()),y) -> y app(app(gcd(),app(s(),x)),|0|()) -> app(s(),x) app(app(gcd(),app(s(),x)),app(s(),y)) -> app(app(app(if_gcd(),app(app(le(),y),x)),app(s(),x)),app(s(),y)) app(app(app(if_gcd(),true()),app(s(),x)),app(s(),y)) -> app(app(gcd(),app(app(minus(),x),y)),app(s(),y)) app(app(app(if_gcd(),false()),app(s(),x)),app(s(),y)) -> app(app(gcd(),app(app(minus(),y),x)),app(s(),x)) app(app(map(),f),nil()) -> nil() app(app(map(),f),app(app(cons(),x),xs)) -> app(app(cons(),app(f,x)),app(app(map(),f),xs)) app(app(filter(),f),nil()) -> nil() app(app(filter(),f),app(app(cons(),x),xs)) -> app(app(app(app(filter2(),app(f,x)),f),x),xs) app(app(app(app(filter2(),true()),f),x),xs) -> app(app(cons(),x),app(app(filter(),f),xs)) app(app(app(app(filter2(),false()),f),x),xs) -> app(app(filter(),f),xs) Instead we prove termination of the uncurried system: app(cons_0(),y) -> cons_1(y) app(cons_1(x1),y) -> cons_2(x1,y) app(filter_0(),y) -> filter_1(y) app(filter_1(x1),y) -> filter_2(x1,y) app(filter2_0(),y) -> filter2_1(y) app(filter2_1(x1),y) -> filter2_2(x1,y) app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) app(gcd_0(),y) -> gcd_1(y) app(gcd_1(x1),y) -> gcd_2(x1,y) app(if_gcd_0(),y) -> if_gcd_1(y) app(if_gcd_1(x1),y) -> if_gcd_2(x1,y) app(if_gcd_2(x1,x2),y) -> if_gcd_3(x1,x2,y) app(le_0(),y) -> le_1(y) app(le_1(x1),y) -> le_2(x1,y) app(map_0(),y) -> map_1(y) app(map_1(x1),y) -> map_2(x1,y) app(minus_0(),y) -> minus_1(y) app(minus_1(x1),y) -> minus_2(x1,y) app(pred_0(),y) -> pred_1(y) app(s_0(),y) -> s_1(y) le_2(|0|_0(),y) -> true_0() le_2(s_1(x),|0|_0()) -> false_0() le_2(s_1(x),s_1(y)) -> le_2(x,y) pred_1(s_1(x)) -> x minus_2(x,|0|_0()) -> x minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) gcd_2(|0|_0(),y) -> y gcd_2(s_1(x),|0|_0()) -> s_1(x) gcd_2(s_1(x),s_1(y)) -> if_gcd_3(le_2(y,x),s_1(x),s_1(y)) if_gcd_3(true_0(),s_1(x),s_1(y)) -> gcd_2(minus_2(x,y),s_1(y)) if_gcd_3(false_0(),s_1(x),s_1(y)) -> gcd_2(minus_2(y,x),s_1(x)) map_2(f,nil_0()) -> nil_0() map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) filter_2(f,nil_0()) -> nil_0() filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(filter_1(x1),y) -> filter_2#(x1,y) p2: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p3: app#(gcd_1(x1),y) -> gcd_2#(x1,y) p4: app#(if_gcd_2(x1,x2),y) -> if_gcd_3#(x1,x2,y) p5: app#(le_1(x1),y) -> le_2#(x1,y) p6: app#(map_1(x1),y) -> map_2#(x1,y) p7: app#(minus_1(x1),y) -> minus_2#(x1,y) p8: app#(pred_0(),y) -> pred_1#(y) p9: le_2#(s_1(x),s_1(y)) -> le_2#(x,y) p10: minus_2#(x,s_1(y)) -> pred_1#(minus_2(x,y)) p11: minus_2#(x,s_1(y)) -> minus_2#(x,y) p12: gcd_2#(s_1(x),s_1(y)) -> if_gcd_3#(le_2(y,x),s_1(x),s_1(y)) p13: gcd_2#(s_1(x),s_1(y)) -> le_2#(y,x) p14: if_gcd_3#(true_0(),s_1(x),s_1(y)) -> gcd_2#(minus_2(x,y),s_1(y)) p15: if_gcd_3#(true_0(),s_1(x),s_1(y)) -> minus_2#(x,y) p16: if_gcd_3#(false_0(),s_1(x),s_1(y)) -> gcd_2#(minus_2(y,x),s_1(x)) p17: if_gcd_3#(false_0(),s_1(x),s_1(y)) -> minus_2#(y,x) p18: map_2#(f,cons_2(x,xs)) -> app#(f,x) p19: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p20: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p21: filter_2#(f,cons_2(x,xs)) -> app#(f,x) p22: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs) p23: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(filter_0(),y) -> filter_1(y) r4: app(filter_1(x1),y) -> filter_2(x1,y) r5: app(filter2_0(),y) -> filter2_1(y) r6: app(filter2_1(x1),y) -> filter2_2(x1,y) r7: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r8: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r9: app(gcd_0(),y) -> gcd_1(y) r10: app(gcd_1(x1),y) -> gcd_2(x1,y) r11: app(if_gcd_0(),y) -> if_gcd_1(y) r12: app(if_gcd_1(x1),y) -> if_gcd_2(x1,y) r13: app(if_gcd_2(x1,x2),y) -> if_gcd_3(x1,x2,y) r14: app(le_0(),y) -> le_1(y) r15: app(le_1(x1),y) -> le_2(x1,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: app(minus_0(),y) -> minus_1(y) r19: app(minus_1(x1),y) -> minus_2(x1,y) r20: app(pred_0(),y) -> pred_1(y) r21: app(s_0(),y) -> s_1(y) r22: le_2(|0|_0(),y) -> true_0() r23: le_2(s_1(x),|0|_0()) -> false_0() r24: le_2(s_1(x),s_1(y)) -> le_2(x,y) r25: pred_1(s_1(x)) -> x r26: minus_2(x,|0|_0()) -> x r27: minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) r28: gcd_2(|0|_0(),y) -> y r29: gcd_2(s_1(x),|0|_0()) -> s_1(x) r30: gcd_2(s_1(x),s_1(y)) -> if_gcd_3(le_2(y,x),s_1(x),s_1(y)) r31: if_gcd_3(true_0(),s_1(x),s_1(y)) -> gcd_2(minus_2(x,y),s_1(y)) r32: if_gcd_3(false_0(),s_1(x),s_1(y)) -> gcd_2(minus_2(y,x),s_1(x)) r33: map_2(f,nil_0()) -> nil_0() r34: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r35: filter_2(f,nil_0()) -> nil_0() r36: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r37: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r38: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The estimated dependency graph contains the following SCCs: {p1, p2, p6, p18, p19, p20, p21, p22, p23} {p12, p14, p16} {p9} {p11} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: app#(filter_1(x1),y) -> filter_2#(x1,y) p2: filter_2#(f,cons_2(x,xs)) -> app#(f,x) p3: app#(map_1(x1),y) -> map_2#(x1,y) p4: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p5: map_2#(f,cons_2(x,xs)) -> app#(f,x) p6: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p7: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) p8: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p9: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(filter_0(),y) -> filter_1(y) r4: app(filter_1(x1),y) -> filter_2(x1,y) r5: app(filter2_0(),y) -> filter2_1(y) r6: app(filter2_1(x1),y) -> filter2_2(x1,y) r7: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r8: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r9: app(gcd_0(),y) -> gcd_1(y) r10: app(gcd_1(x1),y) -> gcd_2(x1,y) r11: app(if_gcd_0(),y) -> if_gcd_1(y) r12: app(if_gcd_1(x1),y) -> if_gcd_2(x1,y) r13: app(if_gcd_2(x1,x2),y) -> if_gcd_3(x1,x2,y) r14: app(le_0(),y) -> le_1(y) r15: app(le_1(x1),y) -> le_2(x1,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: app(minus_0(),y) -> minus_1(y) r19: app(minus_1(x1),y) -> minus_2(x1,y) r20: app(pred_0(),y) -> pred_1(y) r21: app(s_0(),y) -> s_1(y) r22: le_2(|0|_0(),y) -> true_0() r23: le_2(s_1(x),|0|_0()) -> false_0() r24: le_2(s_1(x),s_1(y)) -> le_2(x,y) r25: pred_1(s_1(x)) -> x r26: minus_2(x,|0|_0()) -> x r27: minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) r28: gcd_2(|0|_0(),y) -> y r29: gcd_2(s_1(x),|0|_0()) -> s_1(x) r30: gcd_2(s_1(x),s_1(y)) -> if_gcd_3(le_2(y,x),s_1(x),s_1(y)) r31: if_gcd_3(true_0(),s_1(x),s_1(y)) -> gcd_2(minus_2(x,y),s_1(y)) r32: if_gcd_3(false_0(),s_1(x),s_1(y)) -> gcd_2(minus_2(y,x),s_1(x)) r33: map_2(f,nil_0()) -> nil_0() r34: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r35: filter_2(f,nil_0()) -> nil_0() r36: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r37: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r38: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r1, r3, r5, r22, r23, r24, r26, r28, r29 Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: max/plus interpretation on natural numbers: app#_A(x1,x2) = max{15, x2 + 9} filter_1_A(x1) = 6 filter_2#_A(x1,x2) = max{7, x2 + 3} cons_2_A(x1,x2) = max{13, x1 + 6, x2 + 6} map_1_A(x1) = 6 map_2#_A(x1,x2) = max{8, x2 + 3} filter2_3_A(x1,x2,x3) = max{6, x1 - 1} filter2_4#_A(x1,x2,x3,x4) = max{14, x4 + 8} false_0_A = 0 app_A(x1,x2) = 6 true_0_A = 0 cons_0_A = 7 cons_1_A(x1) = 6 filter_0_A = 6 filter2_0_A = 7 filter2_1_A(x1) = 6 le_2_A(x1,x2) = max{3, x2 - 28} |0|_0_A = 18 s_1_A(x1) = x1 + 27 minus_2_A(x1,x2) = max{x1 + 37, x2 - 58} gcd_2_A(x1,x2) = max{x1 + 10, x2 + 9} base order 2: marked-algebra reduction triple (>=A, >=A!, >A!): max/plus interpretation on natural numbers: app#_A(x1,x2) = max{1, x1 - 120, x2 - 40} filter_1_A(x1) = max{51, x1 + 12} filter_2#_A(x1,x2) = max{1, x1 - 108, x2 - 52} cons_2_A(x1,x2) = max{51, x1 + 12, x2 + 4} map_1_A(x1) = x1 + 54 map_2#_A(x1,x2) = max{1, x1 - 66, x2 - 52} filter2_3_A(x1,x2,x3) = max{x1 - 215, x2 + 99, x3 + 119} filter2_4#_A(x1,x2,x3,x4) = max{1, x2 - 108, x3 - 40, x4 - 48} false_0_A = 51 app_A(x1,x2) = max{51, x1 - 107, x2 + 12} true_0_A = 51 cons_0_A = 61 cons_1_A(x1) = max{51, x1 - 1} filter_0_A = 52 filter2_0_A = 54 filter2_1_A(x1) = max{51, x1 - 1} le_2_A(x1,x2) = max{51, x1 - 108, x2 - 12} |0|_0_A = 0 s_1_A(x1) = max{13, x1 + 11} minus_2_A(x1,x2) = max{10, x1 + 1, x2 - 15} gcd_2_A(x1,x2) = max{16, x1 + 6, x2 + 1} app#!_A(x1,x2) = 1 filter_1!_A(x1) = max{7, x1 - 1} filter_2#!_A(x1,x2) = 21 cons_2!_A(x1,x2) = max{x1 + 48, x2 + 23} map_1!_A(x1) = x1 + 7 map_2#!_A(x1,x2) = max{49, x1 - 120, x2 - 1} filter2_3!_A(x1,x2,x3) = max{154, x1 - 56, x2 - 1, x3 - 2} filter2_4#!_A(x1,x2,x3,x4) = max{22, x2, x3 - 3, x4 - 1} false_0!_A = 1 app!_A(x1,x2) = max{49, x1 - 53, x2 + 6} true_0!_A = 20 cons_0!_A = 8 cons_1!_A(x1) = max{7, x1 - 1} filter_0!_A = 1 filter2_0!_A = 6 filter2_1!_A(x1) = max{7, x1 - 54} le_2!_A(x1,x2) = max{49, x1 - 272, x2 - 14} |0|_0!_A = 21 s_1!_A(x1) = max{60, x1 - 273} minus_2!_A(x1,x2) = max{19, x1 - 2, x2 - 15} gcd_2!_A(x1,x2) = max{60, x2 - 282} partial status: pi(app#) = [] pi(filter_1) = [] pi(filter_2#) = [2] pi(cons_2) = [] pi(map_1) = [] pi(map_2#) = [2] pi(filter2_3) = [] pi(filter2_4#) = [] pi(false_0) = [] pi(app) = [] pi(true_0) = [] pi(cons_0) = [] pi(cons_1) = [] pi(filter_0) = [] pi(filter2_0) = [] pi(filter2_1) = [] pi(le_2) = [] pi(|0|_0) = [] pi(s_1) = [1] pi(minus_2) = [1] pi(gcd_2) = [] The following rules are removed: p1, p2, p3, p4, p5, p6, p7, p8, p9 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: gcd_2#(s_1(x),s_1(y)) -> if_gcd_3#(le_2(y,x),s_1(x),s_1(y)) p2: if_gcd_3#(false_0(),s_1(x),s_1(y)) -> gcd_2#(minus_2(y,x),s_1(x)) p3: if_gcd_3#(true_0(),s_1(x),s_1(y)) -> gcd_2#(minus_2(x,y),s_1(y)) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(filter_0(),y) -> filter_1(y) r4: app(filter_1(x1),y) -> filter_2(x1,y) r5: app(filter2_0(),y) -> filter2_1(y) r6: app(filter2_1(x1),y) -> filter2_2(x1,y) r7: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r8: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r9: app(gcd_0(),y) -> gcd_1(y) r10: app(gcd_1(x1),y) -> gcd_2(x1,y) r11: app(if_gcd_0(),y) -> if_gcd_1(y) r12: app(if_gcd_1(x1),y) -> if_gcd_2(x1,y) r13: app(if_gcd_2(x1,x2),y) -> if_gcd_3(x1,x2,y) r14: app(le_0(),y) -> le_1(y) r15: app(le_1(x1),y) -> le_2(x1,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: app(minus_0(),y) -> minus_1(y) r19: app(minus_1(x1),y) -> minus_2(x1,y) r20: app(pred_0(),y) -> pred_1(y) r21: app(s_0(),y) -> s_1(y) r22: le_2(|0|_0(),y) -> true_0() r23: le_2(s_1(x),|0|_0()) -> false_0() r24: le_2(s_1(x),s_1(y)) -> le_2(x,y) r25: pred_1(s_1(x)) -> x r26: minus_2(x,|0|_0()) -> x r27: minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) r28: gcd_2(|0|_0(),y) -> y r29: gcd_2(s_1(x),|0|_0()) -> s_1(x) r30: gcd_2(s_1(x),s_1(y)) -> if_gcd_3(le_2(y,x),s_1(x),s_1(y)) r31: if_gcd_3(true_0(),s_1(x),s_1(y)) -> gcd_2(minus_2(x,y),s_1(y)) r32: if_gcd_3(false_0(),s_1(x),s_1(y)) -> gcd_2(minus_2(y,x),s_1(x)) r33: map_2(f,nil_0()) -> nil_0() r34: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r35: filter_2(f,nil_0()) -> nil_0() r36: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r37: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r38: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r22, r23, r24, r25, r26, r27 Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: max/plus interpretation on natural numbers: gcd_2#_A(x1,x2) = 6 s_1_A(x1) = max{17, x1 + 9} if_gcd_3#_A(x1,x2,x3) = max{1, x1 - 2} le_2_A(x1,x2) = 8 false_0_A = 8 minus_2_A(x1,x2) = max{7, x1 + 1, x2 - 19} true_0_A = 8 |0|_0_A = 9 pred_1_A(x1) = max{5, x1 - 8} base order 2: marked-algebra reduction triple (>=A, >=A!, >A!): max/plus interpretation on natural numbers: gcd_2#_A(x1,x2) = max{0, x1 - 45, x2 - 74} s_1_A(x1) = max{44, x1 + 30} if_gcd_3#_A(x1,x2,x3) = max{0, x1 - 40, x2 - 73, x3 - 74} le_2_A(x1,x2) = max{13, x1 - 4, x2 - 1} false_0_A = 2 minus_2_A(x1,x2) = max{17, x1 + 1, x2 - 46} true_0_A = 0 |0|_0_A = 0 pred_1_A(x1) = max{17, x1 - 18} gcd_2#!_A(x1,x2) = max{4, x1 - 23, x2 - 25} s_1!_A(x1) = x1 + 5 if_gcd_3#!_A(x1,x2,x3) = max{20, x1 + 8, x2 - 23, x3 - 25} le_2!_A(x1,x2) = max{22, x1 - 45, x2 - 128} false_0!_A = 3 minus_2!_A(x1,x2) = max{21, x2 - 127} true_0!_A = 19 |0|_0!_A = 20 pred_1!_A(x1) = max{22, x1 - 128} partial status: pi(gcd_2#) = [] pi(s_1) = [] pi(if_gcd_3#) = [] pi(le_2) = [] pi(false_0) = [] pi(minus_2) = [1] pi(true_0) = [] pi(|0|_0) = [] pi(pred_1) = [] The following rules are removed: p2 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: gcd_2#(s_1(x),s_1(y)) -> if_gcd_3#(le_2(y,x),s_1(x),s_1(y)) p2: if_gcd_3#(true_0(),s_1(x),s_1(y)) -> gcd_2#(minus_2(x,y),s_1(y)) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(filter_0(),y) -> filter_1(y) r4: app(filter_1(x1),y) -> filter_2(x1,y) r5: app(filter2_0(),y) -> filter2_1(y) r6: app(filter2_1(x1),y) -> filter2_2(x1,y) r7: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r8: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r9: app(gcd_0(),y) -> gcd_1(y) r10: app(gcd_1(x1),y) -> gcd_2(x1,y) r11: app(if_gcd_0(),y) -> if_gcd_1(y) r12: app(if_gcd_1(x1),y) -> if_gcd_2(x1,y) r13: app(if_gcd_2(x1,x2),y) -> if_gcd_3(x1,x2,y) r14: app(le_0(),y) -> le_1(y) r15: app(le_1(x1),y) -> le_2(x1,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: app(minus_0(),y) -> minus_1(y) r19: app(minus_1(x1),y) -> minus_2(x1,y) r20: app(pred_0(),y) -> pred_1(y) r21: app(s_0(),y) -> s_1(y) r22: le_2(|0|_0(),y) -> true_0() r23: le_2(s_1(x),|0|_0()) -> false_0() r24: le_2(s_1(x),s_1(y)) -> le_2(x,y) r25: pred_1(s_1(x)) -> x r26: minus_2(x,|0|_0()) -> x r27: minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) r28: gcd_2(|0|_0(),y) -> y r29: gcd_2(s_1(x),|0|_0()) -> s_1(x) r30: gcd_2(s_1(x),s_1(y)) -> if_gcd_3(le_2(y,x),s_1(x),s_1(y)) r31: if_gcd_3(true_0(),s_1(x),s_1(y)) -> gcd_2(minus_2(x,y),s_1(y)) r32: if_gcd_3(false_0(),s_1(x),s_1(y)) -> gcd_2(minus_2(y,x),s_1(x)) r33: map_2(f,nil_0()) -> nil_0() r34: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r35: filter_2(f,nil_0()) -> nil_0() r36: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r37: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r38: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The estimated dependency graph contains the following SCCs: {p1, p2} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: gcd_2#(s_1(x),s_1(y)) -> if_gcd_3#(le_2(y,x),s_1(x),s_1(y)) p2: if_gcd_3#(true_0(),s_1(x),s_1(y)) -> gcd_2#(minus_2(x,y),s_1(y)) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(filter_0(),y) -> filter_1(y) r4: app(filter_1(x1),y) -> filter_2(x1,y) r5: app(filter2_0(),y) -> filter2_1(y) r6: app(filter2_1(x1),y) -> filter2_2(x1,y) r7: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r8: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r9: app(gcd_0(),y) -> gcd_1(y) r10: app(gcd_1(x1),y) -> gcd_2(x1,y) r11: app(if_gcd_0(),y) -> if_gcd_1(y) r12: app(if_gcd_1(x1),y) -> if_gcd_2(x1,y) r13: app(if_gcd_2(x1,x2),y) -> if_gcd_3(x1,x2,y) r14: app(le_0(),y) -> le_1(y) r15: app(le_1(x1),y) -> le_2(x1,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: app(minus_0(),y) -> minus_1(y) r19: app(minus_1(x1),y) -> minus_2(x1,y) r20: app(pred_0(),y) -> pred_1(y) r21: app(s_0(),y) -> s_1(y) r22: le_2(|0|_0(),y) -> true_0() r23: le_2(s_1(x),|0|_0()) -> false_0() r24: le_2(s_1(x),s_1(y)) -> le_2(x,y) r25: pred_1(s_1(x)) -> x r26: minus_2(x,|0|_0()) -> x r27: minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) r28: gcd_2(|0|_0(),y) -> y r29: gcd_2(s_1(x),|0|_0()) -> s_1(x) r30: gcd_2(s_1(x),s_1(y)) -> if_gcd_3(le_2(y,x),s_1(x),s_1(y)) r31: if_gcd_3(true_0(),s_1(x),s_1(y)) -> gcd_2(minus_2(x,y),s_1(y)) r32: if_gcd_3(false_0(),s_1(x),s_1(y)) -> gcd_2(minus_2(y,x),s_1(x)) r33: map_2(f,nil_0()) -> nil_0() r34: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r35: filter_2(f,nil_0()) -> nil_0() r36: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r37: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r38: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r22, r23, r24, r25, r26, r27 Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: max/plus interpretation on natural numbers: gcd_2#_A(x1,x2) = max{24, x1 + 8} s_1_A(x1) = max{25, x1 + 19} if_gcd_3#_A(x1,x2,x3) = max{x1 + 22, x2 + 1} le_2_A(x1,x2) = max{4, x2 - 20} true_0_A = 1 minus_2_A(x1,x2) = max{10, x1 + 8} |0|_0_A = 2 false_0_A = 3 pred_1_A(x1) = max{9, x1 - 11} base order 2: marked-algebra reduction triple (>=A, >=A!, >A!): max/plus interpretation on natural numbers: gcd_2#_A(x1,x2) = max{0, x1 - 20, x2 - 30} s_1_A(x1) = max{18, x1 + 12} if_gcd_3#_A(x1,x2,x3) = max{0, x1 - 42, x2 - 31, x3 - 30} le_2_A(x1,x2) = max{41, x1 - 28, x2 - 14} true_0_A = 2 minus_2_A(x1,x2) = max{9, x1 + 1, x2 - 20} |0|_0_A = 13 false_0_A = 0 pred_1_A(x1) = max{9, x1 - 10} gcd_2#!_A(x1,x2) = max{0, x1 - 79, x2 - 111} s_1!_A(x1) = max{0, x1 - 66} if_gcd_3#!_A(x1,x2,x3) = max{0, x1 - 71, x2 - 81, x3 - 111} le_2!_A(x1,x2) = max{0, x2 - 66} true_0!_A = 0 minus_2!_A(x1,x2) = 0 |0|_0!_A = 1 false_0!_A = 0 pred_1!_A(x1) = max{2, x1 - 67} partial status: pi(gcd_2#) = [] pi(s_1) = [1] pi(if_gcd_3#) = [] pi(le_2) = [] pi(true_0) = [] pi(minus_2) = [] pi(|0|_0) = [] pi(false_0) = [] pi(pred_1) = [] The following rules are removed: p1, p2 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: le_2#(s_1(x),s_1(y)) -> le_2#(x,y) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(filter_0(),y) -> filter_1(y) r4: app(filter_1(x1),y) -> filter_2(x1,y) r5: app(filter2_0(),y) -> filter2_1(y) r6: app(filter2_1(x1),y) -> filter2_2(x1,y) r7: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r8: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r9: app(gcd_0(),y) -> gcd_1(y) r10: app(gcd_1(x1),y) -> gcd_2(x1,y) r11: app(if_gcd_0(),y) -> if_gcd_1(y) r12: app(if_gcd_1(x1),y) -> if_gcd_2(x1,y) r13: app(if_gcd_2(x1,x2),y) -> if_gcd_3(x1,x2,y) r14: app(le_0(),y) -> le_1(y) r15: app(le_1(x1),y) -> le_2(x1,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: app(minus_0(),y) -> minus_1(y) r19: app(minus_1(x1),y) -> minus_2(x1,y) r20: app(pred_0(),y) -> pred_1(y) r21: app(s_0(),y) -> s_1(y) r22: le_2(|0|_0(),y) -> true_0() r23: le_2(s_1(x),|0|_0()) -> false_0() r24: le_2(s_1(x),s_1(y)) -> le_2(x,y) r25: pred_1(s_1(x)) -> x r26: minus_2(x,|0|_0()) -> x r27: minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) r28: gcd_2(|0|_0(),y) -> y r29: gcd_2(s_1(x),|0|_0()) -> s_1(x) r30: gcd_2(s_1(x),s_1(y)) -> if_gcd_3(le_2(y,x),s_1(x),s_1(y)) r31: if_gcd_3(true_0(),s_1(x),s_1(y)) -> gcd_2(minus_2(x,y),s_1(y)) r32: if_gcd_3(false_0(),s_1(x),s_1(y)) -> gcd_2(minus_2(y,x),s_1(x)) r33: map_2(f,nil_0()) -> nil_0() r34: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r35: filter_2(f,nil_0()) -> nil_0() r36: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r37: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r38: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of (no rules) Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: max/plus interpretation on natural numbers: le_2#_A(x1,x2) = max{15, x1 - 14, x2 - 31} s_1_A(x1) = x1 + 30 base order 2: marked-algebra reduction triple (>=A, >=A!, >A!): max/plus interpretation on natural numbers: le_2#_A(x1,x2) = max{0, x1 - 2, x2 - 2} s_1_A(x1) = max{9, x1 + 1} le_2#!_A(x1,x2) = max{10, x1 - 10, x2 - 68} s_1!_A(x1) = max{9, x1 - 69} partial status: pi(le_2#) = [] pi(s_1) = [1] The following rules are removed: p1 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: minus_2#(x,s_1(y)) -> minus_2#(x,y) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(filter_0(),y) -> filter_1(y) r4: app(filter_1(x1),y) -> filter_2(x1,y) r5: app(filter2_0(),y) -> filter2_1(y) r6: app(filter2_1(x1),y) -> filter2_2(x1,y) r7: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r8: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r9: app(gcd_0(),y) -> gcd_1(y) r10: app(gcd_1(x1),y) -> gcd_2(x1,y) r11: app(if_gcd_0(),y) -> if_gcd_1(y) r12: app(if_gcd_1(x1),y) -> if_gcd_2(x1,y) r13: app(if_gcd_2(x1,x2),y) -> if_gcd_3(x1,x2,y) r14: app(le_0(),y) -> le_1(y) r15: app(le_1(x1),y) -> le_2(x1,y) r16: app(map_0(),y) -> map_1(y) r17: app(map_1(x1),y) -> map_2(x1,y) r18: app(minus_0(),y) -> minus_1(y) r19: app(minus_1(x1),y) -> minus_2(x1,y) r20: app(pred_0(),y) -> pred_1(y) r21: app(s_0(),y) -> s_1(y) r22: le_2(|0|_0(),y) -> true_0() r23: le_2(s_1(x),|0|_0()) -> false_0() r24: le_2(s_1(x),s_1(y)) -> le_2(x,y) r25: pred_1(s_1(x)) -> x r26: minus_2(x,|0|_0()) -> x r27: minus_2(x,s_1(y)) -> pred_1(minus_2(x,y)) r28: gcd_2(|0|_0(),y) -> y r29: gcd_2(s_1(x),|0|_0()) -> s_1(x) r30: gcd_2(s_1(x),s_1(y)) -> if_gcd_3(le_2(y,x),s_1(x),s_1(y)) r31: if_gcd_3(true_0(),s_1(x),s_1(y)) -> gcd_2(minus_2(x,y),s_1(y)) r32: if_gcd_3(false_0(),s_1(x),s_1(y)) -> gcd_2(minus_2(y,x),s_1(x)) r33: map_2(f,nil_0()) -> nil_0() r34: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r35: filter_2(f,nil_0()) -> nil_0() r36: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r37: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r38: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of r22, r23 Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: max/plus interpretation on natural numbers: minus_2#_A(x1,x2) = max{1, x1 - 1} s_1_A(x1) = 0 le_2_A(x1,x2) = max{10, x1 - 13, x2 - 13} |0|_0_A = 6 true_0_A = 3 false_0_A = 1 base order 2: marked-algebra reduction triple (>=A, >=A!, >A!): max/plus interpretation on natural numbers: minus_2#_A(x1,x2) = max{0, x2 - 23} s_1_A(x1) = max{97, x1 + 22} le_2_A(x1,x2) = max{52, x1 - 98, x2 - 23} |0|_0_A = 22 true_0_A = 0 false_0_A = 2 minus_2#!_A(x1,x2) = max{2, x2 - 23} s_1!_A(x1) = 1 le_2!_A(x1,x2) = max{6, x1 - 98, x2 - 98} |0|_0!_A = 3 true_0!_A = 2 false_0!_A = 2 partial status: pi(minus_2#) = [] pi(s_1) = [] pi(le_2) = [] pi(|0|_0) = [] pi(true_0) = [] pi(false_0) = [] The following rules are removed: p1 Then no dependency pair remains.