YES We show the termination of the TRS R: app(app(app(if(),true()),xs),ys) -> xs app(app(app(if(),false()),xs),ys) -> ys app(app(sub(),x),|0|()) -> x app(app(sub(),app(s(),x)),app(s(),y)) -> app(app(sub(),x),y) app(app(gtr(),|0|()),y) -> false() app(app(gtr(),app(s(),x)),|0|()) -> true() app(app(gtr(),app(s(),x)),app(s(),y)) -> app(app(gtr(),x),y) app(app(d(),x),|0|()) -> true() app(app(d(),app(s(),x)),app(s(),y)) -> app(app(app(if(),app(app(gtr(),x),y)),false()),app(app(d(),app(s(),x)),app(app(sub(),y),x))) app(len(),nil()) -> |0|() app(len(),app(app(cons(),x),xs)) -> app(s(),app(len(),xs)) app(app(filter(),p),nil()) -> nil() app(app(filter(),p),app(app(cons(),x),xs)) -> app(app(app(if(),app(p,x)),app(app(cons(),x),app(app(filter(),p),xs))),app(app(filter(),p),xs)) Instead we prove termination of the uncurried system: app(cons_0(),y) -> cons_1(y) app(cons_1(x1),y) -> cons_2(x1,y) app(d_0(),y) -> d_1(y) app(d_1(x1),y) -> d_2(x1,y) app(filter_0(),y) -> filter_1(y) app(filter_1(x1),y) -> filter_2(x1,y) app(gtr_0(),y) -> gtr_1(y) app(gtr_1(x1),y) -> gtr_2(x1,y) app(if_0(),y) -> if_1(y) app(if_1(x1),y) -> if_2(x1,y) app(if_2(x1,x2),y) -> if_3(x1,x2,y) app(len_0(),y) -> len_1(y) app(s_0(),y) -> s_1(y) app(sub_0(),y) -> sub_1(y) app(sub_1(x1),y) -> sub_2(x1,y) if_3(true_0(),xs,ys) -> xs if_3(false_0(),xs,ys) -> ys sub_2(x,|0|_0()) -> x sub_2(s_1(x),s_1(y)) -> sub_2(x,y) gtr_2(|0|_0(),y) -> false_0() gtr_2(s_1(x),|0|_0()) -> true_0() gtr_2(s_1(x),s_1(y)) -> gtr_2(x,y) d_2(x,|0|_0()) -> true_0() d_2(s_1(x),s_1(y)) -> if_3(gtr_2(x,y),false_0(),d_2(s_1(x),sub_2(y,x))) len_1(nil_0()) -> |0|_0() len_1(cons_2(x,xs)) -> s_1(len_1(xs)) filter_2(p,nil_0()) -> nil_0() filter_2(p,cons_2(x,xs)) -> if_3(app(p,x),cons_2(x,filter_2(p,xs)),filter_2(p,xs)) -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(d_1(x1),y) -> d_2#(x1,y) p2: app#(filter_1(x1),y) -> filter_2#(x1,y) p3: app#(gtr_1(x1),y) -> gtr_2#(x1,y) p4: app#(if_2(x1,x2),y) -> if_3#(x1,x2,y) p5: app#(len_0(),y) -> len_1#(y) p6: app#(sub_1(x1),y) -> sub_2#(x1,y) p7: sub_2#(s_1(x),s_1(y)) -> sub_2#(x,y) p8: gtr_2#(s_1(x),s_1(y)) -> gtr_2#(x,y) p9: d_2#(s_1(x),s_1(y)) -> if_3#(gtr_2(x,y),false_0(),d_2(s_1(x),sub_2(y,x))) p10: d_2#(s_1(x),s_1(y)) -> gtr_2#(x,y) p11: d_2#(s_1(x),s_1(y)) -> d_2#(s_1(x),sub_2(y,x)) p12: d_2#(s_1(x),s_1(y)) -> sub_2#(y,x) p13: len_1#(cons_2(x,xs)) -> len_1#(xs) p14: filter_2#(p,cons_2(x,xs)) -> if_3#(app(p,x),cons_2(x,filter_2(p,xs)),filter_2(p,xs)) p15: filter_2#(p,cons_2(x,xs)) -> app#(p,x) p16: filter_2#(p,cons_2(x,xs)) -> filter_2#(p,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(d_0(),y) -> d_1(y) r4: app(d_1(x1),y) -> d_2(x1,y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(gtr_0(),y) -> gtr_1(y) r8: app(gtr_1(x1),y) -> gtr_2(x1,y) r9: app(if_0(),y) -> if_1(y) r10: app(if_1(x1),y) -> if_2(x1,y) r11: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r12: app(len_0(),y) -> len_1(y) r13: app(s_0(),y) -> s_1(y) r14: app(sub_0(),y) -> sub_1(y) r15: app(sub_1(x1),y) -> sub_2(x1,y) r16: if_3(true_0(),xs,ys) -> xs r17: if_3(false_0(),xs,ys) -> ys r18: sub_2(x,|0|_0()) -> x r19: sub_2(s_1(x),s_1(y)) -> sub_2(x,y) r20: gtr_2(|0|_0(),y) -> false_0() r21: gtr_2(s_1(x),|0|_0()) -> true_0() r22: gtr_2(s_1(x),s_1(y)) -> gtr_2(x,y) r23: d_2(x,|0|_0()) -> true_0() r24: d_2(s_1(x),s_1(y)) -> if_3(gtr_2(x,y),false_0(),d_2(s_1(x),sub_2(y,x))) r25: len_1(nil_0()) -> |0|_0() r26: len_1(cons_2(x,xs)) -> s_1(len_1(xs)) r27: filter_2(p,nil_0()) -> nil_0() r28: filter_2(p,cons_2(x,xs)) -> if_3(app(p,x),cons_2(x,filter_2(p,xs)),filter_2(p,xs)) The estimated dependency graph contains the following SCCs: {p2, p15, p16} {p11} {p8} {p13} {p7} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: filter_2#(p,cons_2(x,xs)) -> app#(p,x) p2: app#(filter_1(x1),y) -> filter_2#(x1,y) p3: filter_2#(p,cons_2(x,xs)) -> filter_2#(p,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(d_0(),y) -> d_1(y) r4: app(d_1(x1),y) -> d_2(x1,y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(gtr_0(),y) -> gtr_1(y) r8: app(gtr_1(x1),y) -> gtr_2(x1,y) r9: app(if_0(),y) -> if_1(y) r10: app(if_1(x1),y) -> if_2(x1,y) r11: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r12: app(len_0(),y) -> len_1(y) r13: app(s_0(),y) -> s_1(y) r14: app(sub_0(),y) -> sub_1(y) r15: app(sub_1(x1),y) -> sub_2(x1,y) r16: if_3(true_0(),xs,ys) -> xs r17: if_3(false_0(),xs,ys) -> ys r18: sub_2(x,|0|_0()) -> x r19: sub_2(s_1(x),s_1(y)) -> sub_2(x,y) r20: gtr_2(|0|_0(),y) -> false_0() r21: gtr_2(s_1(x),|0|_0()) -> true_0() r22: gtr_2(s_1(x),s_1(y)) -> gtr_2(x,y) r23: d_2(x,|0|_0()) -> true_0() r24: d_2(s_1(x),s_1(y)) -> if_3(gtr_2(x,y),false_0(),d_2(s_1(x),sub_2(y,x))) r25: len_1(nil_0()) -> |0|_0() r26: len_1(cons_2(x,xs)) -> s_1(len_1(xs)) r27: filter_2(p,nil_0()) -> nil_0() r28: filter_2(p,cons_2(x,xs)) -> if_3(app(p,x),cons_2(x,filter_2(p,xs)),filter_2(p,xs)) The set of usable rules consists of (no rules) Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: trivial reduction triple (T x T, T x T, Φ) base order 2: lexicographic combination of reduction triples: 1. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: filter_2#_A(x1,x2) = x1 + x2 cons_2_A(x1,x2) = x1 + x2 + 9 app#_A(x1,x2) = x1 + x2 filter_1_A(x1) = x1 + 2 filter_2#!_A(x1,x2) = 3 cons_2!_A(x1,x2) = x1 + x2 + 19 app#!_A(x1,x2) = 4 filter_1!_A(x1) = 2 2. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: filter_2#_A(x1,x2) = x1 + x2 cons_2_A(x1,x2) = x1 + x2 + 6 app#_A(x1,x2) = x1 + x2 filter_1_A(x1) = x1 filter_2#!_A(x1,x2) = 0 cons_2!_A(x1,x2) = x1 + 5 app#!_A(x1,x2) = x1 + x2 + 1 filter_1!_A(x1) = 3 partial status: pi(filter_2#) = [2] pi(cons_2) = [1, 2] pi(app#) = [2] pi(filter_1) = [1] The following rules are removed: p1, p2, p3 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: d_2#(s_1(x),s_1(y)) -> d_2#(s_1(x),sub_2(y,x)) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(d_0(),y) -> d_1(y) r4: app(d_1(x1),y) -> d_2(x1,y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(gtr_0(),y) -> gtr_1(y) r8: app(gtr_1(x1),y) -> gtr_2(x1,y) r9: app(if_0(),y) -> if_1(y) r10: app(if_1(x1),y) -> if_2(x1,y) r11: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r12: app(len_0(),y) -> len_1(y) r13: app(s_0(),y) -> s_1(y) r14: app(sub_0(),y) -> sub_1(y) r15: app(sub_1(x1),y) -> sub_2(x1,y) r16: if_3(true_0(),xs,ys) -> xs r17: if_3(false_0(),xs,ys) -> ys r18: sub_2(x,|0|_0()) -> x r19: sub_2(s_1(x),s_1(y)) -> sub_2(x,y) r20: gtr_2(|0|_0(),y) -> false_0() r21: gtr_2(s_1(x),|0|_0()) -> true_0() r22: gtr_2(s_1(x),s_1(y)) -> gtr_2(x,y) r23: d_2(x,|0|_0()) -> true_0() r24: d_2(s_1(x),s_1(y)) -> if_3(gtr_2(x,y),false_0(),d_2(s_1(x),sub_2(y,x))) r25: len_1(nil_0()) -> |0|_0() r26: len_1(cons_2(x,xs)) -> s_1(len_1(xs)) r27: filter_2(p,nil_0()) -> nil_0() r28: filter_2(p,cons_2(x,xs)) -> if_3(app(p,x),cons_2(x,filter_2(p,xs)),filter_2(p,xs)) The set of usable rules consists of r18, r19 Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: trivial reduction triple (T x T, T x T, Φ) base order 2: lexicographic combination of reduction triples: 1. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: d_2#_A(x1,x2) = x2 s_1_A(x1) = x1 + 11 sub_2_A(x1,x2) = x1 + 10 |0|_0_A() = 11 d_2#!_A(x1,x2) = x1 + x2 s_1!_A(x1) = 31 sub_2!_A(x1,x2) = 23 |0|_0!_A() = 27 2. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: d_2#_A(x1,x2) = x2 s_1_A(x1) = x1 + 6 sub_2_A(x1,x2) = x1 + 5 |0|_0_A() = 4 d_2#!_A(x1,x2) = x1 + x2 s_1!_A(x1) = 13 sub_2!_A(x1,x2) = x1 + x2 + 14 |0|_0!_A() = 8 partial status: pi(d_2#) = [1] pi(s_1) = [1] pi(sub_2) = [1] pi(|0|_0) = [] The following rules are removed: p1 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: gtr_2#(s_1(x),s_1(y)) -> gtr_2#(x,y) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(d_0(),y) -> d_1(y) r4: app(d_1(x1),y) -> d_2(x1,y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(gtr_0(),y) -> gtr_1(y) r8: app(gtr_1(x1),y) -> gtr_2(x1,y) r9: app(if_0(),y) -> if_1(y) r10: app(if_1(x1),y) -> if_2(x1,y) r11: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r12: app(len_0(),y) -> len_1(y) r13: app(s_0(),y) -> s_1(y) r14: app(sub_0(),y) -> sub_1(y) r15: app(sub_1(x1),y) -> sub_2(x1,y) r16: if_3(true_0(),xs,ys) -> xs r17: if_3(false_0(),xs,ys) -> ys r18: sub_2(x,|0|_0()) -> x r19: sub_2(s_1(x),s_1(y)) -> sub_2(x,y) r20: gtr_2(|0|_0(),y) -> false_0() r21: gtr_2(s_1(x),|0|_0()) -> true_0() r22: gtr_2(s_1(x),s_1(y)) -> gtr_2(x,y) r23: d_2(x,|0|_0()) -> true_0() r24: d_2(s_1(x),s_1(y)) -> if_3(gtr_2(x,y),false_0(),d_2(s_1(x),sub_2(y,x))) r25: len_1(nil_0()) -> |0|_0() r26: len_1(cons_2(x,xs)) -> s_1(len_1(xs)) r27: filter_2(p,nil_0()) -> nil_0() r28: filter_2(p,cons_2(x,xs)) -> if_3(app(p,x),cons_2(x,filter_2(p,xs)),filter_2(p,xs)) The set of usable rules consists of (no rules) Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: trivial reduction triple (T x T, T x T, Φ) base order 2: lexicographic combination of reduction triples: 1. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: gtr_2#_A(x1,x2) = x1 + x2 s_1_A(x1) = x1 + 3 gtr_2#!_A(x1,x2) = x1 + x2 s_1!_A(x1) = 5 2. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: gtr_2#_A(x1,x2) = x1 + x2 s_1_A(x1) = x1 + 6 gtr_2#!_A(x1,x2) = 15 s_1!_A(x1) = 14 partial status: pi(gtr_2#) = [1, 2] pi(s_1) = [1] The following rules are removed: p1 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: len_1#(cons_2(x,xs)) -> len_1#(xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(d_0(),y) -> d_1(y) r4: app(d_1(x1),y) -> d_2(x1,y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(gtr_0(),y) -> gtr_1(y) r8: app(gtr_1(x1),y) -> gtr_2(x1,y) r9: app(if_0(),y) -> if_1(y) r10: app(if_1(x1),y) -> if_2(x1,y) r11: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r12: app(len_0(),y) -> len_1(y) r13: app(s_0(),y) -> s_1(y) r14: app(sub_0(),y) -> sub_1(y) r15: app(sub_1(x1),y) -> sub_2(x1,y) r16: if_3(true_0(),xs,ys) -> xs r17: if_3(false_0(),xs,ys) -> ys r18: sub_2(x,|0|_0()) -> x r19: sub_2(s_1(x),s_1(y)) -> sub_2(x,y) r20: gtr_2(|0|_0(),y) -> false_0() r21: gtr_2(s_1(x),|0|_0()) -> true_0() r22: gtr_2(s_1(x),s_1(y)) -> gtr_2(x,y) r23: d_2(x,|0|_0()) -> true_0() r24: d_2(s_1(x),s_1(y)) -> if_3(gtr_2(x,y),false_0(),d_2(s_1(x),sub_2(y,x))) r25: len_1(nil_0()) -> |0|_0() r26: len_1(cons_2(x,xs)) -> s_1(len_1(xs)) r27: filter_2(p,nil_0()) -> nil_0() r28: filter_2(p,cons_2(x,xs)) -> if_3(app(p,x),cons_2(x,filter_2(p,xs)),filter_2(p,xs)) The set of usable rules consists of r14 Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: trivial reduction triple (T x T, T x T, Φ) base order 2: lexicographic combination of reduction triples: 1. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: len_1#_A(x1) = x1 cons_2_A(x1,x2) = x2 + 2 app_A(x1,x2) = 1 sub_0_A() = 1 sub_1_A(x1) = 1 len_1#!_A(x1) = 0 cons_2!_A(x1,x2) = x1 + 12 app!_A(x1,x2) = x1 + 9 sub_0!_A() = 0 sub_1!_A(x1) = 7 2. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: len_1#_A(x1) = x1 cons_2_A(x1,x2) = x2 + 2 app_A(x1,x2) = 1 sub_0_A() = 1 sub_1_A(x1) = 1 len_1#!_A(x1) = 0 cons_2!_A(x1,x2) = x2 + 7 app!_A(x1,x2) = x1 + x2 + 8 sub_0!_A() = 0 sub_1!_A(x1) = 5 partial status: pi(len_1#) = [1] pi(cons_2) = [2] pi(app) = [2] pi(sub_0) = [] pi(sub_1) = [] The following rules are removed: p1 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: sub_2#(s_1(x),s_1(y)) -> sub_2#(x,y) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(d_0(),y) -> d_1(y) r4: app(d_1(x1),y) -> d_2(x1,y) r5: app(filter_0(),y) -> filter_1(y) r6: app(filter_1(x1),y) -> filter_2(x1,y) r7: app(gtr_0(),y) -> gtr_1(y) r8: app(gtr_1(x1),y) -> gtr_2(x1,y) r9: app(if_0(),y) -> if_1(y) r10: app(if_1(x1),y) -> if_2(x1,y) r11: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r12: app(len_0(),y) -> len_1(y) r13: app(s_0(),y) -> s_1(y) r14: app(sub_0(),y) -> sub_1(y) r15: app(sub_1(x1),y) -> sub_2(x1,y) r16: if_3(true_0(),xs,ys) -> xs r17: if_3(false_0(),xs,ys) -> ys r18: sub_2(x,|0|_0()) -> x r19: sub_2(s_1(x),s_1(y)) -> sub_2(x,y) r20: gtr_2(|0|_0(),y) -> false_0() r21: gtr_2(s_1(x),|0|_0()) -> true_0() r22: gtr_2(s_1(x),s_1(y)) -> gtr_2(x,y) r23: d_2(x,|0|_0()) -> true_0() r24: d_2(s_1(x),s_1(y)) -> if_3(gtr_2(x,y),false_0(),d_2(s_1(x),sub_2(y,x))) r25: len_1(nil_0()) -> |0|_0() r26: len_1(cons_2(x,xs)) -> s_1(len_1(xs)) r27: filter_2(p,nil_0()) -> nil_0() r28: filter_2(p,cons_2(x,xs)) -> if_3(app(p,x),cons_2(x,filter_2(p,xs)),filter_2(p,xs)) The set of usable rules consists of (no rules) Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: trivial reduction triple (T x T, T x T, Φ) base order 2: lexicographic combination of reduction triples: 1. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: sub_2#_A(x1,x2) = x1 + x2 s_1_A(x1) = x1 + 2 sub_2#!_A(x1,x2) = x1 s_1!_A(x1) = 5 2. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: sub_2#_A(x1,x2) = x1 + x2 s_1_A(x1) = x1 + 6 sub_2#!_A(x1,x2) = x1 + 9 s_1!_A(x1) = 8 partial status: pi(sub_2#) = [1, 2] pi(s_1) = [1] The following rules are removed: p1 Then no dependency pair remains.