YES We show the termination of the TRS R: app(D(),t()) -> |1|() app(D(),constant()) -> |0|() app(D(),app(app(+(),x),y)) -> app(app(+(),app(D(),x)),app(D(),y)) app(D(),app(app(*(),x),y)) -> app(app(+(),app(app(*(),y),app(D(),x))),app(app(*(),x),app(D(),y))) app(D(),app(app(-(),x),y)) -> app(app(-(),app(D(),x)),app(D(),y)) app(D(),app(minus(),x)) -> app(minus(),app(D(),x)) app(D(),app(app(div(),x),y)) -> app(app(-(),app(app(div(),app(D(),x)),y)),app(app(div(),app(app(*(),x),app(D(),y))),app(app(pow(),y),|2|()))) app(D(),app(ln(),x)) -> app(app(div(),app(D(),x)),x) app(D(),app(app(pow(),x),y)) -> app(app(+(),app(app(*(),app(app(*(),y),app(app(pow(),x),app(app(-(),y),|1|())))),app(D(),x))),app(app(*(),app(app(*(),app(app(pow(),x),y)),app(ln(),x))),app(D(),y))) app(app(map(),f),nil()) -> nil() app(app(map(),f),app(app(cons(),x),xs)) -> app(app(cons(),app(f,x)),app(app(map(),f),xs)) app(app(filter(),f),nil()) -> nil() app(app(filter(),f),app(app(cons(),x),xs)) -> app(app(app(app(filter2(),app(f,x)),f),x),xs) app(app(app(app(filter2(),true()),f),x),xs) -> app(app(cons(),x),app(app(filter(),f),xs)) app(app(app(app(filter2(),false()),f),x),xs) -> app(app(filter(),f),xs) Instead we prove termination of the uncurried system: app(*_0(),y) -> *_1(y) app(*_1(x1),y) -> *_2(x1,y) app(+_0(),y) -> +_1(y) app(+_1(x1),y) -> +_2(x1,y) app(-_0(),y) -> -_1(y) app(-_1(x1),y) -> -_2(x1,y) app(D_0(),y) -> D_1(y) app(cons_0(),y) -> cons_1(y) app(cons_1(x1),y) -> cons_2(x1,y) app(div_0(),y) -> div_1(y) app(div_1(x1),y) -> div_2(x1,y) app(filter_0(),y) -> filter_1(y) app(filter_1(x1),y) -> filter_2(x1,y) app(filter2_0(),y) -> filter2_1(y) app(filter2_1(x1),y) -> filter2_2(x1,y) app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) app(ln_0(),y) -> ln_1(y) app(map_0(),y) -> map_1(y) app(map_1(x1),y) -> map_2(x1,y) app(minus_0(),y) -> minus_1(y) app(pow_0(),y) -> pow_1(y) app(pow_1(x1),y) -> pow_2(x1,y) D_1(t_0()) -> |1|_0() D_1(constant_0()) -> |0|_0() D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) D_1(minus_1(x)) -> minus_1(D_1(x)) D_1(div_2(x,y)) -> -_2(div_2(D_1(x),y),div_2(*_2(x,D_1(y)),pow_2(y,|2|_0()))) D_1(ln_1(x)) -> div_2(D_1(x),x) D_1(pow_2(x,y)) -> +_2(*_2(*_2(y,pow_2(x,-_2(y,|1|_0()))),D_1(x)),*_2(*_2(pow_2(x,y),ln_1(x)),D_1(y))) map_2(f,nil_0()) -> nil_0() map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) filter_2(f,nil_0()) -> nil_0() filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(D_0(),y) -> D_1#(y) p2: app#(filter_1(x1),y) -> filter_2#(x1,y) p3: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p4: app#(map_1(x1),y) -> map_2#(x1,y) p5: D_1#(+_2(x,y)) -> D_1#(x) p6: D_1#(+_2(x,y)) -> D_1#(y) p7: D_1#(*_2(x,y)) -> D_1#(x) p8: D_1#(*_2(x,y)) -> D_1#(y) p9: D_1#(-_2(x,y)) -> D_1#(x) p10: D_1#(-_2(x,y)) -> D_1#(y) p11: D_1#(minus_1(x)) -> D_1#(x) p12: D_1#(div_2(x,y)) -> D_1#(x) p13: D_1#(div_2(x,y)) -> D_1#(y) p14: D_1#(ln_1(x)) -> D_1#(x) p15: D_1#(pow_2(x,y)) -> D_1#(x) p16: D_1#(pow_2(x,y)) -> D_1#(y) p17: map_2#(f,cons_2(x,xs)) -> app#(f,x) p18: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p19: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p20: filter_2#(f,cons_2(x,xs)) -> app#(f,x) p21: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs) p22: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(div_0(),y) -> div_1(y) r11: app(div_1(x1),y) -> div_2(x1,y) r12: app(filter_0(),y) -> filter_1(y) r13: app(filter_1(x1),y) -> filter_2(x1,y) r14: app(filter2_0(),y) -> filter2_1(y) r15: app(filter2_1(x1),y) -> filter2_2(x1,y) r16: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r17: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r18: app(ln_0(),y) -> ln_1(y) r19: app(map_0(),y) -> map_1(y) r20: app(map_1(x1),y) -> map_2(x1,y) r21: app(minus_0(),y) -> minus_1(y) r22: app(pow_0(),y) -> pow_1(y) r23: app(pow_1(x1),y) -> pow_2(x1,y) r24: D_1(t_0()) -> |1|_0() r25: D_1(constant_0()) -> |0|_0() r26: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r27: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r28: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r29: D_1(minus_1(x)) -> minus_1(D_1(x)) r30: D_1(div_2(x,y)) -> -_2(div_2(D_1(x),y),div_2(*_2(x,D_1(y)),pow_2(y,|2|_0()))) r31: D_1(ln_1(x)) -> div_2(D_1(x),x) r32: D_1(pow_2(x,y)) -> +_2(*_2(*_2(y,pow_2(x,-_2(y,|1|_0()))),D_1(x)),*_2(*_2(pow_2(x,y),ln_1(x)),D_1(y))) r33: map_2(f,nil_0()) -> nil_0() r34: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r35: filter_2(f,nil_0()) -> nil_0() r36: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r37: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r38: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The estimated dependency graph contains the following SCCs: {p2, p3, p4, p17, p18, p19, p20, p21, p22} {p5, p6, p7, p8, p9, p10, p11, p12, p13, p14, p15, p16} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(f,cons_2(x,xs)) -> app#(f,x) p2: app#(map_1(x1),y) -> map_2#(x1,y) p3: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p4: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p5: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) p6: filter_2#(f,cons_2(x,xs)) -> app#(f,x) p7: app#(filter_1(x1),y) -> filter_2#(x1,y) p8: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p9: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(div_0(),y) -> div_1(y) r11: app(div_1(x1),y) -> div_2(x1,y) r12: app(filter_0(),y) -> filter_1(y) r13: app(filter_1(x1),y) -> filter_2(x1,y) r14: app(filter2_0(),y) -> filter2_1(y) r15: app(filter2_1(x1),y) -> filter2_2(x1,y) r16: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r17: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r18: app(ln_0(),y) -> ln_1(y) r19: app(map_0(),y) -> map_1(y) r20: app(map_1(x1),y) -> map_2(x1,y) r21: app(minus_0(),y) -> minus_1(y) r22: app(pow_0(),y) -> pow_1(y) r23: app(pow_1(x1),y) -> pow_2(x1,y) r24: D_1(t_0()) -> |1|_0() r25: D_1(constant_0()) -> |0|_0() r26: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r27: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r28: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r29: D_1(minus_1(x)) -> minus_1(D_1(x)) r30: D_1(div_2(x,y)) -> -_2(div_2(D_1(x),y),div_2(*_2(x,D_1(y)),pow_2(y,|2|_0()))) r31: D_1(ln_1(x)) -> div_2(D_1(x),x) r32: D_1(pow_2(x,y)) -> +_2(*_2(*_2(y,pow_2(x,-_2(y,|1|_0()))),D_1(x)),*_2(*_2(pow_2(x,y),ln_1(x)),D_1(y))) r33: map_2(f,nil_0()) -> nil_0() r34: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r35: filter_2(f,nil_0()) -> nil_0() r36: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r37: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r38: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of (no rules) Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: trivial reduction triple (T x T, T x T, Φ) base order 2: lexicographic combination of reduction triples: 1. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: map_2#_A(x1,x2) = x1 + x2 cons_2_A(x1,x2) = x1 + x2 + 5 app#_A(x1,x2) = x1 + x2 map_1_A(x1) = x1 + 3 filter2_3_A(x1,x2,x3) = x1 + x2 + x3 + 7 filter2_4#_A(x1,x2,x3,x4) = x2 + x4 + 3 false_0_A() = 1 filter_2#_A(x1,x2) = x1 + x2 + 3 filter_1_A(x1) = x1 + 3 app_A(x1,x2) = x1 + x2 + 1 true_0_A() = 1 map_2#!_A(x1,x2) = 14 cons_2!_A(x1,x2) = x1 + x2 + 17 app#!_A(x1,x2) = 11 map_1!_A(x1) = 15 filter2_3!_A(x1,x2,x3) = x1 + x3 + 15 filter2_4#!_A(x1,x2,x3,x4) = 12 false_0!_A() = 12 filter_2#!_A(x1,x2) = 12 filter_1!_A(x1) = x1 + 13 app!_A(x1,x2) = 14 true_0!_A() = 0 2. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: map_2#_A(x1,x2) = x1 + x2 cons_2_A(x1,x2) = x1 + x2 + 2 app#_A(x1,x2) = x1 + x2 map_1_A(x1) = x1 filter2_3_A(x1,x2,x3) = x1 + x2 + x3 filter2_4#_A(x1,x2,x3,x4) = x2 + x4 false_0_A() = 1 filter_2#_A(x1,x2) = x1 + x2 filter_1_A(x1) = x1 + 1 app_A(x1,x2) = x2 true_0_A() = 1 map_2#!_A(x1,x2) = 10 cons_2!_A(x1,x2) = x1 + 11 app#!_A(x1,x2) = 9 map_1!_A(x1) = 11 filter2_3!_A(x1,x2,x3) = x1 + x2 + x3 + 13 filter2_4#!_A(x1,x2,x3,x4) = 12 false_0!_A() = 8 filter_2#!_A(x1,x2) = 12 filter_1!_A(x1) = x1 + 13 app!_A(x1,x2) = 10 true_0!_A() = 0 partial status: pi(map_2#) = [1] pi(cons_2) = [] pi(app#) = [1] pi(map_1) = [1] pi(filter2_3) = [1, 2] pi(filter2_4#) = [2] pi(false_0) = [] pi(filter_2#) = [1] pi(filter_1) = [1] pi(app) = [] pi(true_0) = [] The following rules are removed: p1, p2, p4, p6, p7 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) p2: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) p3: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p4: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(div_0(),y) -> div_1(y) r11: app(div_1(x1),y) -> div_2(x1,y) r12: app(filter_0(),y) -> filter_1(y) r13: app(filter_1(x1),y) -> filter_2(x1,y) r14: app(filter2_0(),y) -> filter2_1(y) r15: app(filter2_1(x1),y) -> filter2_2(x1,y) r16: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r17: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r18: app(ln_0(),y) -> ln_1(y) r19: app(map_0(),y) -> map_1(y) r20: app(map_1(x1),y) -> map_2(x1,y) r21: app(minus_0(),y) -> minus_1(y) r22: app(pow_0(),y) -> pow_1(y) r23: app(pow_1(x1),y) -> pow_2(x1,y) r24: D_1(t_0()) -> |1|_0() r25: D_1(constant_0()) -> |0|_0() r26: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r27: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r28: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r29: D_1(minus_1(x)) -> minus_1(D_1(x)) r30: D_1(div_2(x,y)) -> -_2(div_2(D_1(x),y),div_2(*_2(x,D_1(y)),pow_2(y,|2|_0()))) r31: D_1(ln_1(x)) -> div_2(D_1(x),x) r32: D_1(pow_2(x,y)) -> +_2(*_2(*_2(y,pow_2(x,-_2(y,|1|_0()))),D_1(x)),*_2(*_2(pow_2(x,y),ln_1(x)),D_1(y))) r33: map_2(f,nil_0()) -> nil_0() r34: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r35: filter_2(f,nil_0()) -> nil_0() r36: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r37: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r38: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The estimated dependency graph contains the following SCCs: {p1} {p2, p3, p4} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(f,cons_2(x,xs)) -> map_2#(f,xs) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(div_0(),y) -> div_1(y) r11: app(div_1(x1),y) -> div_2(x1,y) r12: app(filter_0(),y) -> filter_1(y) r13: app(filter_1(x1),y) -> filter_2(x1,y) r14: app(filter2_0(),y) -> filter2_1(y) r15: app(filter2_1(x1),y) -> filter2_2(x1,y) r16: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r17: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r18: app(ln_0(),y) -> ln_1(y) r19: app(map_0(),y) -> map_1(y) r20: app(map_1(x1),y) -> map_2(x1,y) r21: app(minus_0(),y) -> minus_1(y) r22: app(pow_0(),y) -> pow_1(y) r23: app(pow_1(x1),y) -> pow_2(x1,y) r24: D_1(t_0()) -> |1|_0() r25: D_1(constant_0()) -> |0|_0() r26: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r27: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r28: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r29: D_1(minus_1(x)) -> minus_1(D_1(x)) r30: D_1(div_2(x,y)) -> -_2(div_2(D_1(x),y),div_2(*_2(x,D_1(y)),pow_2(y,|2|_0()))) r31: D_1(ln_1(x)) -> div_2(D_1(x),x) r32: D_1(pow_2(x,y)) -> +_2(*_2(*_2(y,pow_2(x,-_2(y,|1|_0()))),D_1(x)),*_2(*_2(pow_2(x,y),ln_1(x)),D_1(y))) r33: map_2(f,nil_0()) -> nil_0() r34: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r35: filter_2(f,nil_0()) -> nil_0() r36: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r37: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r38: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of (no rules) Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: trivial reduction triple (T x T, T x T, Φ) base order 2: lexicographic combination of reduction triples: 1. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: map_2#_A(x1,x2) = x2 cons_2_A(x1,x2) = x2 + 2 map_2#!_A(x1,x2) = x2 + 7 cons_2!_A(x1,x2) = x1 + 6 2. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: map_2#_A(x1,x2) = 0 cons_2_A(x1,x2) = x1 + 22 map_2#!_A(x1,x2) = 23 cons_2!_A(x1,x2) = x1 + 22 partial status: pi(map_2#) = [1] pi(cons_2) = [] The following rules are removed: p1 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: filter2_4#(false_0(),f,x,xs) -> filter_2#(f,xs) p2: filter_2#(f,cons_2(x,xs)) -> filter2_4#(app(f,x),f,x,xs) p3: filter2_4#(true_0(),f,x,xs) -> filter_2#(f,xs) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(div_0(),y) -> div_1(y) r11: app(div_1(x1),y) -> div_2(x1,y) r12: app(filter_0(),y) -> filter_1(y) r13: app(filter_1(x1),y) -> filter_2(x1,y) r14: app(filter2_0(),y) -> filter2_1(y) r15: app(filter2_1(x1),y) -> filter2_2(x1,y) r16: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r17: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r18: app(ln_0(),y) -> ln_1(y) r19: app(map_0(),y) -> map_1(y) r20: app(map_1(x1),y) -> map_2(x1,y) r21: app(minus_0(),y) -> minus_1(y) r22: app(pow_0(),y) -> pow_1(y) r23: app(pow_1(x1),y) -> pow_2(x1,y) r24: D_1(t_0()) -> |1|_0() r25: D_1(constant_0()) -> |0|_0() r26: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r27: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r28: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r29: D_1(minus_1(x)) -> minus_1(D_1(x)) r30: D_1(div_2(x,y)) -> -_2(div_2(D_1(x),y),div_2(*_2(x,D_1(y)),pow_2(y,|2|_0()))) r31: D_1(ln_1(x)) -> div_2(D_1(x),x) r32: D_1(pow_2(x,y)) -> +_2(*_2(*_2(y,pow_2(x,-_2(y,|1|_0()))),D_1(x)),*_2(*_2(pow_2(x,y),ln_1(x)),D_1(y))) r33: map_2(f,nil_0()) -> nil_0() r34: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r35: filter_2(f,nil_0()) -> nil_0() r36: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r37: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r38: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of (no rules) Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: trivial reduction triple (T x T, T x T, Φ) base order 2: lexicographic combination of reduction triples: 1. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: filter2_4#_A(x1,x2,x3,x4) = x4 false_0_A() = 1 filter_2#_A(x1,x2) = x2 cons_2_A(x1,x2) = x1 + x2 + 5 app_A(x1,x2) = x1 + x2 + 1 true_0_A() = 1 filter2_4#!_A(x1,x2,x3,x4) = x4 + 2 false_0!_A() = 0 filter_2#!_A(x1,x2) = x2 + 1 cons_2!_A(x1,x2) = 28 app!_A(x1,x2) = x1 + 24 true_0!_A() = 0 2. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: filter2_4#_A(x1,x2,x3,x4) = x4 false_0_A() = 1 filter_2#_A(x1,x2) = x2 cons_2_A(x1,x2) = x1 + x2 + 7 app_A(x1,x2) = x1 + x2 + 2 true_0_A() = 1 filter2_4#!_A(x1,x2,x3,x4) = x4 + 2 false_0!_A() = 0 filter_2#!_A(x1,x2) = x2 + 1 cons_2!_A(x1,x2) = x1 + 21 app!_A(x1,x2) = x1 + 9 true_0!_A() = 0 partial status: pi(filter2_4#) = [2, 4] pi(false_0) = [] pi(filter_2#) = [1, 2] pi(cons_2) = [2] pi(app) = [] pi(true_0) = [] The following rules are removed: p1, p2, p3 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: D_1#(+_2(x,y)) -> D_1#(x) p2: D_1#(pow_2(x,y)) -> D_1#(y) p3: D_1#(pow_2(x,y)) -> D_1#(x) p4: D_1#(ln_1(x)) -> D_1#(x) p5: D_1#(div_2(x,y)) -> D_1#(y) p6: D_1#(div_2(x,y)) -> D_1#(x) p7: D_1#(minus_1(x)) -> D_1#(x) p8: D_1#(-_2(x,y)) -> D_1#(y) p9: D_1#(-_2(x,y)) -> D_1#(x) p10: D_1#(*_2(x,y)) -> D_1#(y) p11: D_1#(*_2(x,y)) -> D_1#(x) p12: D_1#(+_2(x,y)) -> D_1#(y) and R consists of: r1: app(*_0(),y) -> *_1(y) r2: app(*_1(x1),y) -> *_2(x1,y) r3: app(+_0(),y) -> +_1(y) r4: app(+_1(x1),y) -> +_2(x1,y) r5: app(-_0(),y) -> -_1(y) r6: app(-_1(x1),y) -> -_2(x1,y) r7: app(D_0(),y) -> D_1(y) r8: app(cons_0(),y) -> cons_1(y) r9: app(cons_1(x1),y) -> cons_2(x1,y) r10: app(div_0(),y) -> div_1(y) r11: app(div_1(x1),y) -> div_2(x1,y) r12: app(filter_0(),y) -> filter_1(y) r13: app(filter_1(x1),y) -> filter_2(x1,y) r14: app(filter2_0(),y) -> filter2_1(y) r15: app(filter2_1(x1),y) -> filter2_2(x1,y) r16: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r17: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r18: app(ln_0(),y) -> ln_1(y) r19: app(map_0(),y) -> map_1(y) r20: app(map_1(x1),y) -> map_2(x1,y) r21: app(minus_0(),y) -> minus_1(y) r22: app(pow_0(),y) -> pow_1(y) r23: app(pow_1(x1),y) -> pow_2(x1,y) r24: D_1(t_0()) -> |1|_0() r25: D_1(constant_0()) -> |0|_0() r26: D_1(+_2(x,y)) -> +_2(D_1(x),D_1(y)) r27: D_1(*_2(x,y)) -> +_2(*_2(y,D_1(x)),*_2(x,D_1(y))) r28: D_1(-_2(x,y)) -> -_2(D_1(x),D_1(y)) r29: D_1(minus_1(x)) -> minus_1(D_1(x)) r30: D_1(div_2(x,y)) -> -_2(div_2(D_1(x),y),div_2(*_2(x,D_1(y)),pow_2(y,|2|_0()))) r31: D_1(ln_1(x)) -> div_2(D_1(x),x) r32: D_1(pow_2(x,y)) -> +_2(*_2(*_2(y,pow_2(x,-_2(y,|1|_0()))),D_1(x)),*_2(*_2(pow_2(x,y),ln_1(x)),D_1(y))) r33: map_2(f,nil_0()) -> nil_0() r34: map_2(f,cons_2(x,xs)) -> cons_2(app(f,x),map_2(f,xs)) r35: filter_2(f,nil_0()) -> nil_0() r36: filter_2(f,cons_2(x,xs)) -> filter2_4(app(f,x),f,x,xs) r37: filter2_4(true_0(),f,x,xs) -> cons_2(x,filter_2(f,xs)) r38: filter2_4(false_0(),f,x,xs) -> filter_2(f,xs) The set of usable rules consists of (no rules) Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: trivial reduction triple (T x T, T x T, Φ) base order 2: lexicographic combination of reduction triples: 1. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: D_1#_A(x1) = 0 +_2_A(x1,x2) = x1 + x2 + 2 pow_2_A(x1,x2) = x1 + x2 + 2 ln_1_A(x1) = 2 div_2_A(x1,x2) = x2 + 4 minus_1_A(x1) = x1 + 2 -_2_A(x1,x2) = 4 *_2_A(x1,x2) = x1 + x2 + 9 D_1#!_A(x1) = 7 +_2!_A(x1,x2) = 6 pow_2!_A(x1,x2) = 12 ln_1!_A(x1) = 12 div_2!_A(x1,x2) = x1 + 7 minus_1!_A(x1) = 1 -_2!_A(x1,x2) = x1 + 13 *_2!_A(x1,x2) = x2 + 5 2. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: D_1#_A(x1) = x1 +_2_A(x1,x2) = x1 + x2 + 2 pow_2_A(x1,x2) = x1 + x2 + 2 ln_1_A(x1) = x1 + 2 div_2_A(x1,x2) = x1 + x2 + 2 minus_1_A(x1) = x1 + 2 -_2_A(x1,x2) = x1 + x2 + 2 *_2_A(x1,x2) = x1 + x2 + 2 D_1#!_A(x1) = x1 + 6 +_2!_A(x1,x2) = 5 pow_2!_A(x1,x2) = x2 + 10 ln_1!_A(x1) = x1 + 9 div_2!_A(x1,x2) = x2 + 6 minus_1!_A(x1) = 7 -_2!_A(x1,x2) = 5 *_2!_A(x1,x2) = x1 + 3 partial status: pi(D_1#) = [] pi(+_2) = [] pi(pow_2) = [1] pi(ln_1) = [1] pi(div_2) = [] pi(minus_1) = [] pi(-_2) = [] pi(*_2) = [] The following rules are removed: p1, p2, p3, p4, p5, p6, p7, p8, p9, p10, p11, p12 Then no dependency pair remains.