YES We show the termination of the TRS R: app(app(minus(),|0|()),y) -> |0|() app(app(minus(),app(s(),x)),|0|()) -> app(s(),x) app(app(minus(),app(s(),x)),app(s(),y)) -> app(app(minus(),x),y) app(app(le(),|0|()),y) -> true() app(app(le(),app(s(),x)),|0|()) -> false() app(app(le(),app(s(),x)),app(s(),y)) -> app(app(le(),x),y) app(app(app(if(),true()),x),y) -> x app(app(app(if(),false()),x),y) -> y app(perfectp(),|0|()) -> false() app(perfectp(),app(s(),x)) -> app(app(app(app(f(),x),app(s(),|0|())),app(s(),x)),app(s(),x)) app(app(app(app(f(),|0|()),y),|0|()),u) -> true() app(app(app(app(f(),|0|()),y),app(s(),z)),u) -> false() app(app(app(app(f(),app(s(),x)),|0|()),z),u) -> app(app(app(app(f(),x),u),app(app(minus(),z),app(s(),x))),u) app(app(app(app(f(),app(s(),x)),app(s(),y)),z),u) -> app(app(app(if(),app(app(le(),x),y)),app(app(app(app(f(),app(s(),x)),app(app(minus(),y),x)),z),u)),app(app(app(app(f(),x),u),z),u)) app(app(map(),|fun|),nil()) -> nil() app(app(map(),|fun|),app(app(cons(),x),xs)) -> app(app(cons(),app(|fun|,x)),app(app(map(),|fun|),xs)) app(app(filter(),|fun|),nil()) -> nil() app(app(filter(),|fun|),app(app(cons(),x),xs)) -> app(app(app(app(filter2(),app(|fun|,x)),|fun|),x),xs) app(app(app(app(filter2(),true()),|fun|),x),xs) -> app(app(cons(),x),app(app(filter(),|fun|),xs)) app(app(app(app(filter2(),false()),|fun|),x),xs) -> app(app(filter(),|fun|),xs) Instead we prove termination of the uncurried system: app(cons_0(),y) -> cons_1(y) app(cons_1(x1),y) -> cons_2(x1,y) app(f_0(),y) -> f_1(y) app(f_1(x1),y) -> f_2(x1,y) app(f_2(x1,x2),y) -> f_3(x1,x2,y) app(f_3(x1,x2,x3),y) -> f_4(x1,x2,x3,y) app(filter_0(),y) -> filter_1(y) app(filter_1(x1),y) -> filter_2(x1,y) app(filter2_0(),y) -> filter2_1(y) app(filter2_1(x1),y) -> filter2_2(x1,y) app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) app(if_0(),y) -> if_1(y) app(if_1(x1),y) -> if_2(x1,y) app(if_2(x1,x2),y) -> if_3(x1,x2,y) app(le_0(),y) -> le_1(y) app(le_1(x1),y) -> le_2(x1,y) app(map_0(),y) -> map_1(y) app(map_1(x1),y) -> map_2(x1,y) app(minus_0(),y) -> minus_1(y) app(minus_1(x1),y) -> minus_2(x1,y) app(perfectp_0(),y) -> perfectp_1(y) app(s_0(),y) -> s_1(y) minus_2(|0|_0(),y) -> |0|_0() minus_2(s_1(x),|0|_0()) -> s_1(x) minus_2(s_1(x),s_1(y)) -> minus_2(x,y) le_2(|0|_0(),y) -> true_0() le_2(s_1(x),|0|_0()) -> false_0() le_2(s_1(x),s_1(y)) -> le_2(x,y) if_3(true_0(),x,y) -> x if_3(false_0(),x,y) -> y perfectp_1(|0|_0()) -> false_0() perfectp_1(s_1(x)) -> f_4(x,s_1(|0|_0()),s_1(x),s_1(x)) f_4(|0|_0(),y,|0|_0(),u) -> true_0() f_4(|0|_0(),y,s_1(z),u) -> false_0() f_4(s_1(x),|0|_0(),z,u) -> f_4(x,u,minus_2(z,s_1(x)),u) f_4(s_1(x),s_1(y),z,u) -> if_3(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u)) map_2(|fun|,nil_0()) -> nil_0() map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) filter_2(|fun|,nil_0()) -> nil_0() filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: app#(f_3(x1,x2,x3),y) -> f_4#(x1,x2,x3,y) p2: app#(filter_1(x1),y) -> filter_2#(x1,y) p3: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p4: app#(if_2(x1,x2),y) -> if_3#(x1,x2,y) p5: app#(le_1(x1),y) -> le_2#(x1,y) p6: app#(map_1(x1),y) -> map_2#(x1,y) p7: app#(minus_1(x1),y) -> minus_2#(x1,y) p8: app#(perfectp_0(),y) -> perfectp_1#(y) p9: minus_2#(s_1(x),s_1(y)) -> minus_2#(x,y) p10: le_2#(s_1(x),s_1(y)) -> le_2#(x,y) p11: perfectp_1#(s_1(x)) -> f_4#(x,s_1(|0|_0()),s_1(x),s_1(x)) p12: f_4#(s_1(x),|0|_0(),z,u) -> f_4#(x,u,minus_2(z,s_1(x)),u) p13: f_4#(s_1(x),|0|_0(),z,u) -> minus_2#(z,s_1(x)) p14: f_4#(s_1(x),s_1(y),z,u) -> if_3#(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u)) p15: f_4#(s_1(x),s_1(y),z,u) -> le_2#(x,y) p16: f_4#(s_1(x),s_1(y),z,u) -> f_4#(s_1(x),minus_2(y,x),z,u) p17: f_4#(s_1(x),s_1(y),z,u) -> minus_2#(y,x) p18: f_4#(s_1(x),s_1(y),z,u) -> f_4#(x,u,z,u) p19: map_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p20: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) p21: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p22: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p23: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p24: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(f_3(x1,x2,x3),y) -> f_4(x1,x2,x3,y) r7: app(filter_0(),y) -> filter_1(y) r8: app(filter_1(x1),y) -> filter_2(x1,y) r9: app(filter2_0(),y) -> filter2_1(y) r10: app(filter2_1(x1),y) -> filter2_2(x1,y) r11: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r12: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r13: app(if_0(),y) -> if_1(y) r14: app(if_1(x1),y) -> if_2(x1,y) r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r16: app(le_0(),y) -> le_1(y) r17: app(le_1(x1),y) -> le_2(x1,y) r18: app(map_0(),y) -> map_1(y) r19: app(map_1(x1),y) -> map_2(x1,y) r20: app(minus_0(),y) -> minus_1(y) r21: app(minus_1(x1),y) -> minus_2(x1,y) r22: app(perfectp_0(),y) -> perfectp_1(y) r23: app(s_0(),y) -> s_1(y) r24: minus_2(|0|_0(),y) -> |0|_0() r25: minus_2(s_1(x),|0|_0()) -> s_1(x) r26: minus_2(s_1(x),s_1(y)) -> minus_2(x,y) r27: le_2(|0|_0(),y) -> true_0() r28: le_2(s_1(x),|0|_0()) -> false_0() r29: le_2(s_1(x),s_1(y)) -> le_2(x,y) r30: if_3(true_0(),x,y) -> x r31: if_3(false_0(),x,y) -> y r32: perfectp_1(|0|_0()) -> false_0() r33: perfectp_1(s_1(x)) -> f_4(x,s_1(|0|_0()),s_1(x),s_1(x)) r34: f_4(|0|_0(),y,|0|_0(),u) -> true_0() r35: f_4(|0|_0(),y,s_1(z),u) -> false_0() r36: f_4(s_1(x),|0|_0(),z,u) -> f_4(x,u,minus_2(z,s_1(x)),u) r37: f_4(s_1(x),s_1(y),z,u) -> if_3(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u)) r38: map_2(|fun|,nil_0()) -> nil_0() r39: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r40: filter_2(|fun|,nil_0()) -> nil_0() r41: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r42: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r43: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: {p2, p3, p6, p19, p20, p21, p22, p23, p24} {p12, p16, p18} {p10} {p9} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p2: app#(map_1(x1),y) -> map_2#(x1,y) p3: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) p4: app#(filter2_3(x1,x2,x3),y) -> filter2_4#(x1,x2,x3,y) p5: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p6: filter_2#(|fun|,cons_2(x,xs)) -> app#(|fun|,x) p7: app#(filter_1(x1),y) -> filter_2#(x1,y) p8: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p9: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(f_3(x1,x2,x3),y) -> f_4(x1,x2,x3,y) r7: app(filter_0(),y) -> filter_1(y) r8: app(filter_1(x1),y) -> filter_2(x1,y) r9: app(filter2_0(),y) -> filter2_1(y) r10: app(filter2_1(x1),y) -> filter2_2(x1,y) r11: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r12: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r13: app(if_0(),y) -> if_1(y) r14: app(if_1(x1),y) -> if_2(x1,y) r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r16: app(le_0(),y) -> le_1(y) r17: app(le_1(x1),y) -> le_2(x1,y) r18: app(map_0(),y) -> map_1(y) r19: app(map_1(x1),y) -> map_2(x1,y) r20: app(minus_0(),y) -> minus_1(y) r21: app(minus_1(x1),y) -> minus_2(x1,y) r22: app(perfectp_0(),y) -> perfectp_1(y) r23: app(s_0(),y) -> s_1(y) r24: minus_2(|0|_0(),y) -> |0|_0() r25: minus_2(s_1(x),|0|_0()) -> s_1(x) r26: minus_2(s_1(x),s_1(y)) -> minus_2(x,y) r27: le_2(|0|_0(),y) -> true_0() r28: le_2(s_1(x),|0|_0()) -> false_0() r29: le_2(s_1(x),s_1(y)) -> le_2(x,y) r30: if_3(true_0(),x,y) -> x r31: if_3(false_0(),x,y) -> y r32: perfectp_1(|0|_0()) -> false_0() r33: perfectp_1(s_1(x)) -> f_4(x,s_1(|0|_0()),s_1(x),s_1(x)) r34: f_4(|0|_0(),y,|0|_0(),u) -> true_0() r35: f_4(|0|_0(),y,s_1(z),u) -> false_0() r36: f_4(s_1(x),|0|_0(),z,u) -> f_4(x,u,minus_2(z,s_1(x)),u) r37: f_4(s_1(x),s_1(y),z,u) -> if_3(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u)) r38: map_2(|fun|,nil_0()) -> nil_0() r39: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r40: filter_2(|fun|,nil_0()) -> nil_0() r41: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r42: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r43: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r15, r17, r27, r28, r29, r30, r31, r35 Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: trivial reduction triple (T x T, T x T, Φ) base order 2: lexicographic combination of reduction triples: 1. marked-algebra reduction triple (>=A, >=A!, >A!): max/plus interpretation on natural numbers: map_2#_A(x1,x2) = max{1, x1 - 5} cons_2_A(x1,x2) = x2 + 119 app#_A(x1,x2) = max{1, x1 - 17} map_1_A(x1) = max{16, x1 + 12} filter2_3_A(x1,x2,x3) = max{16, x2 + 12, x3 + 13} filter2_4#_A(x1,x2,x3,x4) = max{1, x2 - 5} false_0_A = 7 filter_2#_A(x1,x2) = max{1, x1 - 5} filter_1_A(x1) = max{16, x1 + 13} app_A(x1,x2) = max{x1 - 133, x2 + 11} true_0_A = 11 if_2_A(x1,x2) = max{x1 - 1, x2 + 143} if_3_A(x1,x2,x3) = max{11, x1 - 134, x2, x3} le_1_A(x1) = 14 le_2_A(x1,x2) = 11 |0|_0_A = 87 s_1_A(x1) = max{19, x1 - 134} f_4_A(x1,x2,x3,x4) = max{7, x1 - 143, x2 - 143, x3 - 143, x4 - 143} map_2#!_A(x1,x2) = 114 cons_2!_A(x1,x2) = max{93, x1 + 85, x2 + 91} app#!_A(x1,x2) = 114 map_1!_A(x1) = 113 filter2_3!_A(x1,x2,x3) = max{x1 - 12, x2 + 116, x3 + 116} filter2_4#!_A(x1,x2,x3,x4) = max{115, x2 + 2} false_0!_A = 222 filter_2#!_A(x1,x2) = max{115, x1 + 2} filter_1!_A(x1) = max{116, x1 + 3} app!_A(x1,x2) = max{0, x1 - 15} true_0!_A = 224 if_2!_A(x1,x2) = max{3, x1 - 135, x2 - 1} if_3!_A(x1,x2,x3) = max{x1 - 134, x2 + 127} le_1!_A(x1) = max{225, x1 - 1} le_2!_A(x1,x2) = 225 |0|_0!_A = 223 s_1!_A(x1) = 226 f_4!_A(x1,x2,x3,x4) = max{x1 - 106, x2 + 202, x3 - 17, x4 + 135} 2. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: map_2#_A(x1,x2) = 0 cons_2_A(x1,x2) = 10 app#_A(x1,x2) = 0 map_1_A(x1) = x1 + 5 filter2_3_A(x1,x2,x3) = x1 + x2 + x3 + 7 filter2_4#_A(x1,x2,x3,x4) = 0 false_0_A() = 5 filter_2#_A(x1,x2) = 0 filter_1_A(x1) = x1 + 3 app_A(x1,x2) = x1 + x2 + 1 true_0_A() = 12 if_2_A(x1,x2) = x1 + x2 + 5 if_3_A(x1,x2,x3) = x2 + x3 le_1_A(x1) = x1 + 11 le_2_A(x1,x2) = x2 + 12 |0|_0_A() = 1 s_1_A(x1) = x1 + 3 f_4_A(x1,x2,x3,x4) = x1 + x2 + x3 + x4 + 9 map_2#!_A(x1,x2) = x1 + 5 cons_2!_A(x1,x2) = x1 + 6 app#!_A(x1,x2) = x1 + 1 map_1!_A(x1) = 4 filter2_3!_A(x1,x2,x3) = 0 filter2_4#!_A(x1,x2,x3,x4) = x2 + 9 false_0!_A() = 0 filter_2#!_A(x1,x2) = x1 + 9 filter_1!_A(x1) = x1 + 10 app!_A(x1,x2) = 8 true_0!_A() = 2 if_2!_A(x1,x2) = 6 if_3!_A(x1,x2,x3) = 7 le_1!_A(x1) = 3 le_2!_A(x1,x2) = 3 |0|_0!_A() = 1 s_1!_A(x1) = 4 f_4!_A(x1,x2,x3,x4) = x1 + x2 + x3 + 5 partial status: pi(map_2#) = [1] pi(cons_2) = [2] pi(app#) = [1] pi(map_1) = [1] pi(filter2_3) = [2] pi(filter2_4#) = [2] pi(false_0) = [] pi(filter_2#) = [1] pi(filter_1) = [1] pi(app) = [1, 2] pi(true_0) = [] pi(if_2) = [1, 2] pi(if_3) = [1, 2, 3] pi(le_1) = [1] pi(le_2) = [] pi(|0|_0) = [] pi(s_1) = [1] pi(f_4) = [1, 2] The following rules are removed: p1, p2, p4, p6, p7 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) p2: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p3: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p4: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(f_3(x1,x2,x3),y) -> f_4(x1,x2,x3,y) r7: app(filter_0(),y) -> filter_1(y) r8: app(filter_1(x1),y) -> filter_2(x1,y) r9: app(filter2_0(),y) -> filter2_1(y) r10: app(filter2_1(x1),y) -> filter2_2(x1,y) r11: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r12: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r13: app(if_0(),y) -> if_1(y) r14: app(if_1(x1),y) -> if_2(x1,y) r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r16: app(le_0(),y) -> le_1(y) r17: app(le_1(x1),y) -> le_2(x1,y) r18: app(map_0(),y) -> map_1(y) r19: app(map_1(x1),y) -> map_2(x1,y) r20: app(minus_0(),y) -> minus_1(y) r21: app(minus_1(x1),y) -> minus_2(x1,y) r22: app(perfectp_0(),y) -> perfectp_1(y) r23: app(s_0(),y) -> s_1(y) r24: minus_2(|0|_0(),y) -> |0|_0() r25: minus_2(s_1(x),|0|_0()) -> s_1(x) r26: minus_2(s_1(x),s_1(y)) -> minus_2(x,y) r27: le_2(|0|_0(),y) -> true_0() r28: le_2(s_1(x),|0|_0()) -> false_0() r29: le_2(s_1(x),s_1(y)) -> le_2(x,y) r30: if_3(true_0(),x,y) -> x r31: if_3(false_0(),x,y) -> y r32: perfectp_1(|0|_0()) -> false_0() r33: perfectp_1(s_1(x)) -> f_4(x,s_1(|0|_0()),s_1(x),s_1(x)) r34: f_4(|0|_0(),y,|0|_0(),u) -> true_0() r35: f_4(|0|_0(),y,s_1(z),u) -> false_0() r36: f_4(s_1(x),|0|_0(),z,u) -> f_4(x,u,minus_2(z,s_1(x)),u) r37: f_4(s_1(x),s_1(y),z,u) -> if_3(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u)) r38: map_2(|fun|,nil_0()) -> nil_0() r39: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r40: filter_2(|fun|,nil_0()) -> nil_0() r41: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r42: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r43: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: {p1} {p2, p3, p4} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: map_2#(|fun|,cons_2(x,xs)) -> map_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(f_3(x1,x2,x3),y) -> f_4(x1,x2,x3,y) r7: app(filter_0(),y) -> filter_1(y) r8: app(filter_1(x1),y) -> filter_2(x1,y) r9: app(filter2_0(),y) -> filter2_1(y) r10: app(filter2_1(x1),y) -> filter2_2(x1,y) r11: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r12: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r13: app(if_0(),y) -> if_1(y) r14: app(if_1(x1),y) -> if_2(x1,y) r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r16: app(le_0(),y) -> le_1(y) r17: app(le_1(x1),y) -> le_2(x1,y) r18: app(map_0(),y) -> map_1(y) r19: app(map_1(x1),y) -> map_2(x1,y) r20: app(minus_0(),y) -> minus_1(y) r21: app(minus_1(x1),y) -> minus_2(x1,y) r22: app(perfectp_0(),y) -> perfectp_1(y) r23: app(s_0(),y) -> s_1(y) r24: minus_2(|0|_0(),y) -> |0|_0() r25: minus_2(s_1(x),|0|_0()) -> s_1(x) r26: minus_2(s_1(x),s_1(y)) -> minus_2(x,y) r27: le_2(|0|_0(),y) -> true_0() r28: le_2(s_1(x),|0|_0()) -> false_0() r29: le_2(s_1(x),s_1(y)) -> le_2(x,y) r30: if_3(true_0(),x,y) -> x r31: if_3(false_0(),x,y) -> y r32: perfectp_1(|0|_0()) -> false_0() r33: perfectp_1(s_1(x)) -> f_4(x,s_1(|0|_0()),s_1(x),s_1(x)) r34: f_4(|0|_0(),y,|0|_0(),u) -> true_0() r35: f_4(|0|_0(),y,s_1(z),u) -> false_0() r36: f_4(s_1(x),|0|_0(),z,u) -> f_4(x,u,minus_2(z,s_1(x)),u) r37: f_4(s_1(x),s_1(y),z,u) -> if_3(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u)) r38: map_2(|fun|,nil_0()) -> nil_0() r39: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r40: filter_2(|fun|,nil_0()) -> nil_0() r41: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r42: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r43: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r24 Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: trivial reduction triple (T x T, T x T, Φ) base order 2: lexicographic combination of reduction triples: 1. marked-algebra reduction triple (>=A, >=A!, >A!): max/plus interpretation on natural numbers: map_2#_A(x1,x2) = max{0, x2 - 2} cons_2_A(x1,x2) = max{96, x1 - 1, x2 + 1} minus_2_A(x1,x2) = max{71, x1 - 72, x2} |0|_0_A = 0 map_2#!_A(x1,x2) = 67 cons_2!_A(x1,x2) = max{67, x1 - 7, x2 - 100} minus_2!_A(x1,x2) = max{0, x1 - 72} |0|_0!_A = 0 2. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: map_2#_A(x1,x2) = x2 cons_2_A(x1,x2) = x1 + x2 + 5 minus_2_A(x1,x2) = x1 + 5 |0|_0_A() = 1 map_2#!_A(x1,x2) = x2 + 4 cons_2!_A(x1,x2) = x1 + x2 + 4 minus_2!_A(x1,x2) = 8 |0|_0!_A() = 7 partial status: pi(map_2#) = [2] pi(cons_2) = [2] pi(minus_2) = [] pi(|0|_0) = [] The following rules are removed: p1 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: filter2_4#(false_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) p2: filter_2#(|fun|,cons_2(x,xs)) -> filter2_4#(app(|fun|,x),|fun|,x,xs) p3: filter2_4#(true_0(),|fun|,x,xs) -> filter_2#(|fun|,xs) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(f_3(x1,x2,x3),y) -> f_4(x1,x2,x3,y) r7: app(filter_0(),y) -> filter_1(y) r8: app(filter_1(x1),y) -> filter_2(x1,y) r9: app(filter2_0(),y) -> filter2_1(y) r10: app(filter2_1(x1),y) -> filter2_2(x1,y) r11: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r12: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r13: app(if_0(),y) -> if_1(y) r14: app(if_1(x1),y) -> if_2(x1,y) r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r16: app(le_0(),y) -> le_1(y) r17: app(le_1(x1),y) -> le_2(x1,y) r18: app(map_0(),y) -> map_1(y) r19: app(map_1(x1),y) -> map_2(x1,y) r20: app(minus_0(),y) -> minus_1(y) r21: app(minus_1(x1),y) -> minus_2(x1,y) r22: app(perfectp_0(),y) -> perfectp_1(y) r23: app(s_0(),y) -> s_1(y) r24: minus_2(|0|_0(),y) -> |0|_0() r25: minus_2(s_1(x),|0|_0()) -> s_1(x) r26: minus_2(s_1(x),s_1(y)) -> minus_2(x,y) r27: le_2(|0|_0(),y) -> true_0() r28: le_2(s_1(x),|0|_0()) -> false_0() r29: le_2(s_1(x),s_1(y)) -> le_2(x,y) r30: if_3(true_0(),x,y) -> x r31: if_3(false_0(),x,y) -> y r32: perfectp_1(|0|_0()) -> false_0() r33: perfectp_1(s_1(x)) -> f_4(x,s_1(|0|_0()),s_1(x),s_1(x)) r34: f_4(|0|_0(),y,|0|_0(),u) -> true_0() r35: f_4(|0|_0(),y,s_1(z),u) -> false_0() r36: f_4(s_1(x),|0|_0(),z,u) -> f_4(x,u,minus_2(z,s_1(x)),u) r37: f_4(s_1(x),s_1(y),z,u) -> if_3(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u)) r38: map_2(|fun|,nil_0()) -> nil_0() r39: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r40: filter_2(|fun|,nil_0()) -> nil_0() r41: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r42: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r43: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r24 Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: trivial reduction triple (T x T, T x T, Φ) base order 2: lexicographic combination of reduction triples: 1. marked-algebra reduction triple (>=A, >=A!, >A!): max/plus interpretation on natural numbers: filter2_4#_A(x1,x2,x3,x4) = max{22, x2 - 1, x3 - 1, x4 + 13} false_0_A = 12 filter_2#_A(x1,x2) = max{22, x1 - 1, x2 + 13} cons_2_A(x1,x2) = max{x1 - 13, x2 + 8} app_A(x1,x2) = max{9, x1 - 11, x2 + 8} true_0_A = 12 minus_2_A(x1,x2) = max{46, x1} |0|_0_A = 35 filter2_4#!_A(x1,x2,x3,x4) = max{x3 + 1, x4 + 53} false_0!_A = 0 filter_2#!_A(x1,x2) = x2 + 52 cons_2!_A(x1,x2) = 0 app!_A(x1,x2) = max{60, x2 + 39} true_0!_A = 4 minus_2!_A(x1,x2) = max{37, x1 - 36, x2 - 36} |0|_0!_A = 27 2. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: filter2_4#_A(x1,x2,x3,x4) = 0 false_0_A() = 31 filter_2#_A(x1,x2) = 0 cons_2_A(x1,x2) = x2 + 2 app_A(x1,x2) = x1 + 1 true_0_A() = 17 minus_2_A(x1,x2) = x1 + 15 |0|_0_A() = 1 filter2_4#!_A(x1,x2,x3,x4) = x2 + x4 + 10 false_0!_A() = 8 filter_2#!_A(x1,x2) = x1 + x2 + 9 cons_2!_A(x1,x2) = 5 app!_A(x1,x2) = x1 + 1 true_0!_A() = 8 minus_2!_A(x1,x2) = 13 |0|_0!_A() = 10 partial status: pi(filter2_4#) = [] pi(false_0) = [] pi(filter_2#) = [] pi(cons_2) = [] pi(app) = [1, 2] pi(true_0) = [] pi(minus_2) = [] pi(|0|_0) = [] The following rules are removed: p1, p2, p3 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: f_4#(s_1(x),|0|_0(),z,u) -> f_4#(x,u,minus_2(z,s_1(x)),u) p2: f_4#(s_1(x),s_1(y),z,u) -> f_4#(x,u,z,u) p3: f_4#(s_1(x),s_1(y),z,u) -> f_4#(s_1(x),minus_2(y,x),z,u) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(f_3(x1,x2,x3),y) -> f_4(x1,x2,x3,y) r7: app(filter_0(),y) -> filter_1(y) r8: app(filter_1(x1),y) -> filter_2(x1,y) r9: app(filter2_0(),y) -> filter2_1(y) r10: app(filter2_1(x1),y) -> filter2_2(x1,y) r11: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r12: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r13: app(if_0(),y) -> if_1(y) r14: app(if_1(x1),y) -> if_2(x1,y) r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r16: app(le_0(),y) -> le_1(y) r17: app(le_1(x1),y) -> le_2(x1,y) r18: app(map_0(),y) -> map_1(y) r19: app(map_1(x1),y) -> map_2(x1,y) r20: app(minus_0(),y) -> minus_1(y) r21: app(minus_1(x1),y) -> minus_2(x1,y) r22: app(perfectp_0(),y) -> perfectp_1(y) r23: app(s_0(),y) -> s_1(y) r24: minus_2(|0|_0(),y) -> |0|_0() r25: minus_2(s_1(x),|0|_0()) -> s_1(x) r26: minus_2(s_1(x),s_1(y)) -> minus_2(x,y) r27: le_2(|0|_0(),y) -> true_0() r28: le_2(s_1(x),|0|_0()) -> false_0() r29: le_2(s_1(x),s_1(y)) -> le_2(x,y) r30: if_3(true_0(),x,y) -> x r31: if_3(false_0(),x,y) -> y r32: perfectp_1(|0|_0()) -> false_0() r33: perfectp_1(s_1(x)) -> f_4(x,s_1(|0|_0()),s_1(x),s_1(x)) r34: f_4(|0|_0(),y,|0|_0(),u) -> true_0() r35: f_4(|0|_0(),y,s_1(z),u) -> false_0() r36: f_4(s_1(x),|0|_0(),z,u) -> f_4(x,u,minus_2(z,s_1(x)),u) r37: f_4(s_1(x),s_1(y),z,u) -> if_3(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u)) r38: map_2(|fun|,nil_0()) -> nil_0() r39: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r40: filter_2(|fun|,nil_0()) -> nil_0() r41: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r42: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r43: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r24, r25, r26 Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: trivial reduction triple (T x T, T x T, Φ) base order 2: lexicographic combination of reduction triples: 1. marked-algebra reduction triple (>=A, >=A!, >A!): max/plus interpretation on natural numbers: f_4#_A(x1,x2,x3,x4) = max{0, x1 - 239, x2 - 160, x3 - 81, x4 - 108} s_1_A(x1) = max{132, x1 + 108} |0|_0_A = 52 minus_2_A(x1,x2) = max{80, x1, x2 - 158} f_4#!_A(x1,x2,x3,x4) = max{103, x1 - 109, x2 - 29, x3 - 82, x4 + 21} s_1!_A(x1) = 22 |0|_0!_A = 104 minus_2!_A(x1,x2) = 22 2. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: f_4#_A(x1,x2,x3,x4) = x1 + x3 s_1_A(x1) = x1 + 6 |0|_0_A() = 1 minus_2_A(x1,x2) = x1 + 5 f_4#!_A(x1,x2,x3,x4) = x1 + x3 + 14 s_1!_A(x1) = x1 + 18 |0|_0!_A() = 16 minus_2!_A(x1,x2) = x2 + 15 partial status: pi(f_4#) = [] pi(s_1) = [1] pi(|0|_0) = [] pi(minus_2) = [1, 2] The following rules are removed: p1, p2 -- SCC decomposition. Consider the dependency pair problem (P, R), where P consists of p1: f_4#(s_1(x),s_1(y),z,u) -> f_4#(s_1(x),minus_2(y,x),z,u) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(f_3(x1,x2,x3),y) -> f_4(x1,x2,x3,y) r7: app(filter_0(),y) -> filter_1(y) r8: app(filter_1(x1),y) -> filter_2(x1,y) r9: app(filter2_0(),y) -> filter2_1(y) r10: app(filter2_1(x1),y) -> filter2_2(x1,y) r11: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r12: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r13: app(if_0(),y) -> if_1(y) r14: app(if_1(x1),y) -> if_2(x1,y) r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r16: app(le_0(),y) -> le_1(y) r17: app(le_1(x1),y) -> le_2(x1,y) r18: app(map_0(),y) -> map_1(y) r19: app(map_1(x1),y) -> map_2(x1,y) r20: app(minus_0(),y) -> minus_1(y) r21: app(minus_1(x1),y) -> minus_2(x1,y) r22: app(perfectp_0(),y) -> perfectp_1(y) r23: app(s_0(),y) -> s_1(y) r24: minus_2(|0|_0(),y) -> |0|_0() r25: minus_2(s_1(x),|0|_0()) -> s_1(x) r26: minus_2(s_1(x),s_1(y)) -> minus_2(x,y) r27: le_2(|0|_0(),y) -> true_0() r28: le_2(s_1(x),|0|_0()) -> false_0() r29: le_2(s_1(x),s_1(y)) -> le_2(x,y) r30: if_3(true_0(),x,y) -> x r31: if_3(false_0(),x,y) -> y r32: perfectp_1(|0|_0()) -> false_0() r33: perfectp_1(s_1(x)) -> f_4(x,s_1(|0|_0()),s_1(x),s_1(x)) r34: f_4(|0|_0(),y,|0|_0(),u) -> true_0() r35: f_4(|0|_0(),y,s_1(z),u) -> false_0() r36: f_4(s_1(x),|0|_0(),z,u) -> f_4(x,u,minus_2(z,s_1(x)),u) r37: f_4(s_1(x),s_1(y),z,u) -> if_3(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u)) r38: map_2(|fun|,nil_0()) -> nil_0() r39: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r40: filter_2(|fun|,nil_0()) -> nil_0() r41: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r42: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r43: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The estimated dependency graph contains the following SCCs: {p1} -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: f_4#(s_1(x),s_1(y),z,u) -> f_4#(s_1(x),minus_2(y,x),z,u) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(f_3(x1,x2,x3),y) -> f_4(x1,x2,x3,y) r7: app(filter_0(),y) -> filter_1(y) r8: app(filter_1(x1),y) -> filter_2(x1,y) r9: app(filter2_0(),y) -> filter2_1(y) r10: app(filter2_1(x1),y) -> filter2_2(x1,y) r11: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r12: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r13: app(if_0(),y) -> if_1(y) r14: app(if_1(x1),y) -> if_2(x1,y) r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r16: app(le_0(),y) -> le_1(y) r17: app(le_1(x1),y) -> le_2(x1,y) r18: app(map_0(),y) -> map_1(y) r19: app(map_1(x1),y) -> map_2(x1,y) r20: app(minus_0(),y) -> minus_1(y) r21: app(minus_1(x1),y) -> minus_2(x1,y) r22: app(perfectp_0(),y) -> perfectp_1(y) r23: app(s_0(),y) -> s_1(y) r24: minus_2(|0|_0(),y) -> |0|_0() r25: minus_2(s_1(x),|0|_0()) -> s_1(x) r26: minus_2(s_1(x),s_1(y)) -> minus_2(x,y) r27: le_2(|0|_0(),y) -> true_0() r28: le_2(s_1(x),|0|_0()) -> false_0() r29: le_2(s_1(x),s_1(y)) -> le_2(x,y) r30: if_3(true_0(),x,y) -> x r31: if_3(false_0(),x,y) -> y r32: perfectp_1(|0|_0()) -> false_0() r33: perfectp_1(s_1(x)) -> f_4(x,s_1(|0|_0()),s_1(x),s_1(x)) r34: f_4(|0|_0(),y,|0|_0(),u) -> true_0() r35: f_4(|0|_0(),y,s_1(z),u) -> false_0() r36: f_4(s_1(x),|0|_0(),z,u) -> f_4(x,u,minus_2(z,s_1(x)),u) r37: f_4(s_1(x),s_1(y),z,u) -> if_3(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u)) r38: map_2(|fun|,nil_0()) -> nil_0() r39: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r40: filter_2(|fun|,nil_0()) -> nil_0() r41: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r42: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r43: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r24, r25, r26 Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: trivial reduction triple (T x T, T x T, Φ) base order 2: lexicographic combination of reduction triples: 1. marked-algebra reduction triple (>=A, >=A!, >A!): max/plus interpretation on natural numbers: f_4#_A(x1,x2,x3,x4) = max{0, x1 - 48, x2 - 45, x3 - 4, x4 - 4} s_1_A(x1) = max{44, x1 + 32} minus_2_A(x1,x2) = max{42, x1 + 32, x2 - 45} |0|_0_A = 27 f_4#!_A(x1,x2,x3,x4) = 0 s_1!_A(x1) = 90 minus_2!_A(x1,x2) = 89 |0|_0!_A = 91 2. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: f_4#_A(x1,x2,x3,x4) = x2 s_1_A(x1) = x1 + 6 minus_2_A(x1,x2) = x1 + 5 |0|_0_A() = 1 f_4#!_A(x1,x2,x3,x4) = 11 s_1!_A(x1) = 13 minus_2!_A(x1,x2) = 12 |0|_0!_A() = 11 partial status: pi(f_4#) = [2] pi(s_1) = [1] pi(minus_2) = [1] pi(|0|_0) = [] The following rules are removed: p1 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: le_2#(s_1(x),s_1(y)) -> le_2#(x,y) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(f_3(x1,x2,x3),y) -> f_4(x1,x2,x3,y) r7: app(filter_0(),y) -> filter_1(y) r8: app(filter_1(x1),y) -> filter_2(x1,y) r9: app(filter2_0(),y) -> filter2_1(y) r10: app(filter2_1(x1),y) -> filter2_2(x1,y) r11: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r12: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r13: app(if_0(),y) -> if_1(y) r14: app(if_1(x1),y) -> if_2(x1,y) r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r16: app(le_0(),y) -> le_1(y) r17: app(le_1(x1),y) -> le_2(x1,y) r18: app(map_0(),y) -> map_1(y) r19: app(map_1(x1),y) -> map_2(x1,y) r20: app(minus_0(),y) -> minus_1(y) r21: app(minus_1(x1),y) -> minus_2(x1,y) r22: app(perfectp_0(),y) -> perfectp_1(y) r23: app(s_0(),y) -> s_1(y) r24: minus_2(|0|_0(),y) -> |0|_0() r25: minus_2(s_1(x),|0|_0()) -> s_1(x) r26: minus_2(s_1(x),s_1(y)) -> minus_2(x,y) r27: le_2(|0|_0(),y) -> true_0() r28: le_2(s_1(x),|0|_0()) -> false_0() r29: le_2(s_1(x),s_1(y)) -> le_2(x,y) r30: if_3(true_0(),x,y) -> x r31: if_3(false_0(),x,y) -> y r32: perfectp_1(|0|_0()) -> false_0() r33: perfectp_1(s_1(x)) -> f_4(x,s_1(|0|_0()),s_1(x),s_1(x)) r34: f_4(|0|_0(),y,|0|_0(),u) -> true_0() r35: f_4(|0|_0(),y,s_1(z),u) -> false_0() r36: f_4(s_1(x),|0|_0(),z,u) -> f_4(x,u,minus_2(z,s_1(x)),u) r37: f_4(s_1(x),s_1(y),z,u) -> if_3(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u)) r38: map_2(|fun|,nil_0()) -> nil_0() r39: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r40: filter_2(|fun|,nil_0()) -> nil_0() r41: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r42: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r43: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of r24 Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: trivial reduction triple (T x T, T x T, Φ) base order 2: lexicographic combination of reduction triples: 1. marked-algebra reduction triple (>=A, >=A!, >A!): max/plus interpretation on natural numbers: le_2#_A(x1,x2) = 0 s_1_A(x1) = max{0, x1 - 3} minus_2_A(x1,x2) = max{x1, x2} |0|_0_A = 0 le_2#!_A(x1,x2) = 0 s_1!_A(x1) = 20 minus_2!_A(x1,x2) = max{20, x1 + 2, x2 + 3} |0|_0!_A = 13 2. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: le_2#_A(x1,x2) = x1 + x2 s_1_A(x1) = x1 + 10 minus_2_A(x1,x2) = x1 + x2 + 5 |0|_0_A() = 6 le_2#!_A(x1,x2) = x1 + x2 s_1!_A(x1) = 44 minus_2!_A(x1,x2) = x1 + 33 |0|_0!_A() = 26 partial status: pi(le_2#) = [] pi(s_1) = [] pi(minus_2) = [1] pi(|0|_0) = [] The following rules are removed: p1 Then no dependency pair remains. -- Reduction pair. Consider the dependency pair problem (P, R), where P consists of p1: minus_2#(s_1(x),s_1(y)) -> minus_2#(x,y) and R consists of: r1: app(cons_0(),y) -> cons_1(y) r2: app(cons_1(x1),y) -> cons_2(x1,y) r3: app(f_0(),y) -> f_1(y) r4: app(f_1(x1),y) -> f_2(x1,y) r5: app(f_2(x1,x2),y) -> f_3(x1,x2,y) r6: app(f_3(x1,x2,x3),y) -> f_4(x1,x2,x3,y) r7: app(filter_0(),y) -> filter_1(y) r8: app(filter_1(x1),y) -> filter_2(x1,y) r9: app(filter2_0(),y) -> filter2_1(y) r10: app(filter2_1(x1),y) -> filter2_2(x1,y) r11: app(filter2_2(x1,x2),y) -> filter2_3(x1,x2,y) r12: app(filter2_3(x1,x2,x3),y) -> filter2_4(x1,x2,x3,y) r13: app(if_0(),y) -> if_1(y) r14: app(if_1(x1),y) -> if_2(x1,y) r15: app(if_2(x1,x2),y) -> if_3(x1,x2,y) r16: app(le_0(),y) -> le_1(y) r17: app(le_1(x1),y) -> le_2(x1,y) r18: app(map_0(),y) -> map_1(y) r19: app(map_1(x1),y) -> map_2(x1,y) r20: app(minus_0(),y) -> minus_1(y) r21: app(minus_1(x1),y) -> minus_2(x1,y) r22: app(perfectp_0(),y) -> perfectp_1(y) r23: app(s_0(),y) -> s_1(y) r24: minus_2(|0|_0(),y) -> |0|_0() r25: minus_2(s_1(x),|0|_0()) -> s_1(x) r26: minus_2(s_1(x),s_1(y)) -> minus_2(x,y) r27: le_2(|0|_0(),y) -> true_0() r28: le_2(s_1(x),|0|_0()) -> false_0() r29: le_2(s_1(x),s_1(y)) -> le_2(x,y) r30: if_3(true_0(),x,y) -> x r31: if_3(false_0(),x,y) -> y r32: perfectp_1(|0|_0()) -> false_0() r33: perfectp_1(s_1(x)) -> f_4(x,s_1(|0|_0()),s_1(x),s_1(x)) r34: f_4(|0|_0(),y,|0|_0(),u) -> true_0() r35: f_4(|0|_0(),y,s_1(z),u) -> false_0() r36: f_4(s_1(x),|0|_0(),z,u) -> f_4(x,u,minus_2(z,s_1(x)),u) r37: f_4(s_1(x),s_1(y),z,u) -> if_3(le_2(x,y),f_4(s_1(x),minus_2(y,x),z,u),f_4(x,u,z,u)) r38: map_2(|fun|,nil_0()) -> nil_0() r39: map_2(|fun|,cons_2(x,xs)) -> cons_2(app(|fun|,x),map_2(|fun|,xs)) r40: filter_2(|fun|,nil_0()) -> nil_0() r41: filter_2(|fun|,cons_2(x,xs)) -> filter2_4(app(|fun|,x),|fun|,x,xs) r42: filter2_4(true_0(),|fun|,x,xs) -> cons_2(x,filter_2(|fun|,xs)) r43: filter2_4(false_0(),|fun|,x,xs) -> filter_2(|fun|,xs) The set of usable rules consists of (no rules) Take the reduction pair: generalized weighted path order (>=MG, >G) base order 1: trivial reduction triple (T x T, T x T, Φ) base order 2: lexicographic combination of reduction triples: 1. marked-algebra reduction triple (>=A, >=A!, >A!): max/plus interpretation on natural numbers: minus_2#_A(x1,x2) = max{0, x1 - 155, x2 - 155} s_1_A(x1) = max{267, x1 + 154} minus_2#!_A(x1,x2) = max{74, x1 - 155} s_1!_A(x1) = max{73, x1 - 115} 2. marked-algebra reduction triple (>=A, >=A!, >A!): matrix interpretation with standard point-wise order: carrier: N^1 order: standard order interpretations: minus_2#_A(x1,x2) = x1 + x2 s_1_A(x1) = x1 + 6 minus_2#!_A(x1,x2) = x1 + x2 + 13 s_1!_A(x1) = 12 partial status: pi(minus_2#) = [] pi(s_1) = [] The following rules are removed: p1 Then no dependency pair remains.